Special Binding Data

[jonatan_velarde]

Good morning my SAS friends:

Here i come to be helped, well let me show you this case:

Was made an experiment having 5 observations, the data of the first one was obtained numerically ordered, but the rest was not, even though the number in the second sampling time was bigger that the first sampling, like that:

Data FirstSampling:

input Sample Observ1;

cards;

9    14.00

10    17.00

11    11.00

12    11.00

13    14.00

14    14.00

15    13.00

16    12.00

17    12.00

;

Data SecondSampling;

input Sample    Observ2    Observ3    Observ4    Observ5;

vcards;

1    25.00    6.99    2.64    1.40

4    27.00    7.16    2.68    1.43

12    45.00    8.27    2.88    1.65

7    36.00    7.78    2.79    1.56

13    24.00    6.90    2.63    1.38

5    87.00    9.70    3.11    1.94

6    34.00    7.66    2.77    1.53

11    72.00    9.29    3.05    1.86

2    13.00    5.57    2.36    1.11

10    15.00    5.88    2.42    1.18

8    24.00    6.90    2.63    1.38

18    31.00    7.46    2.73    1.49

17    23.00    6.81    2.61    1.36

3    23.00    6.81    2.61    1.36

16    23.00    6.81    2.61    1.36

15    34.00    7.66    2.77    1.53

9    26.00    7.07    2.66    1.41

19    21.00    6.61    2.57    1.32

20    11.00    5.21    2.28    1.04

14    34.00    7.66    2.77    1.53

;

So here is the problem: that i would like to bind these two datasets, and obtains something like that:

Sample	Observ1	Observ2	Observ3	Observ4	Observ5
1	.	25.00	6.99	2.64	1.40
2	.	13.00	5.57	2.36	1.11
3	.	23.00	6.81	2.61	1.36
4	.	27.00	7.16	2.68	1.43
5	.	87.00	9.70	3.11	1.94
6	.	34.00	7.66	2.77	1.53
7	.	36.00	7.78	2.79	1.56
8	.	24.00	6.90	2.63	1.38
9	14.00	26.00	7.07	2.66	1.41
10	17.00	15.00	5.88	2.42	1.18
11	11.00	72.00	9.29	3.05	1.86
12	11.00	45.00	8.27	2.88	1.65
13	14.00	24.00	6.90	2.63	1.38
14	14.00	34.00	7.66	2.77	1.53
15	13.00	34.00	7.66	2.77	1.53
16	12.00	23.00	6.81	2.61	1.36
17	12.00	23.00	6.81	2.61	1.36
18	.	31.00	7.46	2.73	1.49
19	.	21.00	6.61	2.57	1.32
20	.	11.00	5.21	2.28	1.04

Thank you very much

[slchen]

proc sort data=SecondSampling;

by sample;

run;

data want;

     merge FirstSampling SecondSampling;

    by sample;

run;