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xtc283x
Quartz | Level 8

I have a pipe delimited file that contains several date/time fields with information like this:  '2/8/2015 0:00:00'  What is the datetime function that would read these fields in and allow me to use the daypart() or timepart() functions to break them out separately?

Thanks!

1 ACCEPTED SOLUTION

Accepted Solutions
AskoLötjönen
Quartz | Level 8

Anydtdtm informat is quite clever :

data have;

attrib dtm format=datetime21. informat=anydtdtm21.;

input dtm ;

cards;

2/8/2015 0:00:00

;

run;

data want;

  set have;

attrib datep format=date9.;

attrib timep format=time8.;

datep=datepart(dtm);

timep=timepart(dtm);

run;

View solution in original post

4 REPLIES 4
AskoLötjönen
Quartz | Level 8

Anydtdtm informat is quite clever :

data have;

attrib dtm format=datetime21. informat=anydtdtm21.;

input dtm ;

cards;

2/8/2015 0:00:00

;

run;

data want;

  set have;

attrib datep format=date9.;

attrib timep format=time8.;

datep=datepart(dtm);

timep=timepart(dtm);

run;

xtc283x
Quartz | Level 8

Thanks, Asko. That works!

BrunoSilva
Quartz | Level 8

Hello,

This litle script will help you to find any informat in the future Smiley Happy

%let STR_TO_FIND=%str(2/8/2015 0:00:00);

data find_informat;

    length source $ 100;

    format result datetime.;

    set sashelp.vformat;

    where fmttype eq "I";

    source_str="&STR_TO_FIND.";

    result=inputn(source_str,fmtname);

    if result ne .;

    keep source_str result fmtname;

run;

Best regards,

xtc283x
Quartz | Level 8

Thanks, Bruno!

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