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anilgvdbm
Quartz | Level 8

Hi All,

 

I have a datasets 3000 lets say test0001 to test3000 and the variable names are same in all the datasets. I want to append all 3000 files in to one file.

 

Please suggest me any short simple way to do this task.

 

 

Regards,

Anil

 

2 REPLIES 2
Kurt_Bremser
Super User

proc append can only handle one dataset to append.

But you can use a datastep with wildcards:

data basetest;
input x;
cards;
1
;
run;

data add0001;
input x;
cards;
2
;
run;

data add0002;
input x;
cards;
3
;
run;

data basetest;
set
  basetest
  add:
;
run;
RW9
Diamond | Level 26 RW9
Diamond | Level 26

First off, don't write all in upper case - I will change the subject.

Secondly why do you have 3000 datasets all the same, sounds like your running some procedure over data and outputting to separate datasets - this is not an efficient methodology and then leads to questions like yours.  Look up by group processing.  In your original data create a grouping variable, then do your procedure with the by group - it is faster, less coding, less disk space, and simpler to work with.  E.g. I want to do means on all groups of age 1-10, 11-20, 20+

data inter;
  set have;
  length group $20;
  if 1 <= age <= 10 then group="Group 1";
  else if 11 <= age <= 20 then group="Group 2";
  else group="Group 3";
run;

proc means data=inter;
  by group;     /* key line */
  var weight;
  output out=want n=n mean=mean;
run;

This will process one dataset, by the given group, and produce one dataset with all the output needed.

If you have another point, please give full details.

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