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SOORISAS
Calcite | Level 5

I want to transpose a dataset like this

Month  Customer

1         AAAAA

2         AAAAA

3         AAAAA

4         AAAAA

1         BBBBB

2         BBBBB

to

1            2            3              4              5

AAAAA  AAAAA   AAAAA    AAAAA     AAAAA

BBBBB  BBBBB

1 ACCEPTED SOLUTION

Accepted Solutions
Oleg_L
Obsidian | Level 7

data c;

infile cards;

input month customer : $5.;

cards;

1 AAAAA

2 AAAAA

3 AAAAA

4 AAAAA

1 BBBBB

2 BBBBB

;

proc sort data=c; by month;run;

proc transpose data=c out=c1; by month; var customer; run;

proc transpose data=c1 (drop=_name_) out=c2; var month col:; run;

View solution in original post

5 REPLIES 5
Tom
Super User Tom
Super User

You need a third variable that indicates when to start a new row in the output dataset.

The code below creates one by assuming when month number is less than previous month value then you have started a new group.

data have ;

input month customer $;

if month < lag(month) then group+1;

cards;

1 AAAAA

2 AAAAA

3 AAAAA

4 AAAAA

1 BBBBB

2 BBBBB

;;;;

proc transpose data=have out=want ;

  by group ;

  id month;

  var customer;

run;

proc print width=min;

run;

robertrao
Quartz | Level 8

Hi Tom,

Before we transpose, the dataset was sorted by CUSTOMER and BY MONTH???

Thanks

Oleg_L
Obsidian | Level 7

data c;

infile cards;

input month customer : $5.;

cards;

1 AAAAA

2 AAAAA

3 AAAAA

4 AAAAA

1 BBBBB

2 BBBBB

;

proc sort data=c; by month;run;

proc transpose data=c out=c1; by month; var customer; run;

proc transpose data=c1 (drop=_name_) out=c2; var month col:; run;

SOORISAS
Calcite | Level 5

Thanks Oleg_L, I got exactly what I want without any intermediate blanks.

Smiley Happy

Pallav
Calcite | Level 5

data have ;

input month customer $;

cards;

1 AAAAA

2 AAAAA

3 AAAAA

4 AAAAA

1 BBBBB

2 BBBBB

;

Run;

option validvarname = any;

proc transpose data = have out = tran(drop = _name_ customer);

id month;

by customer;

var customer;

Run;

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