BookmarkSubscribeRSS Feed
🔒 This topic is solved and locked. Need further help from the community? Please sign in and ask a new question.
ybz12003
Rhodochrosite | Level 12

Hello:

 

I have two dataset, test1 and test2.   I would like to find the match based on the following situation:

 

(Test1 "Analysis" = Test2 "Analysis") and  [ Test1 "Product" = any of the Test2 ("Class" / "Component" / "Product") ]

 

I have the inner join code below, I found out that the "Cleft Lip +/- Palate" and "ATENOLOL" are shown twice in the result.   Any idea why?  How to fix the problem?  Thanks.

 

data test1;

infile datalines dlm='|';

input name : $20. Analysis : $100. Product : $100.;

datalines;

 

Ali| Cleft Lip +/- Palate| LABETOLOL|

Ali| Cleft Lip +/- Palate| ATENOLOL|

Ali| VSDs (Excludes VSDavc)| ATENOLOL|

Ali| VSDs (Excludes VSDavc)| FLUCONAZOLE|

Carol| Choanal Atresia| LEVOTHYROXINE SODIUM|

Carol| Cleft Lip +/- Palate| ATENOLOL|

Carol| Intestinal Atresia/Stenosis| EPHEDRA|

Malyn| TGA +/- DORV| ALBUTEROL SULFATE|

Malyn| TOF +/- PA, DORV -TGA| BUTALBITAL|

Malyn| Esoph Atresia +/- TEF| FLONASE|

;

 

proc sort data=test1; by analysis; run;

 

data test2;

infile datalines dlm='|';

input Analysis : $100. Class : $100. Component : $100. Product : $100.;

datalines;

 

Cleft Lip +/- Palate| LEVOTHYROXINE SODIUM| | |

VSDs (Excludes VSDavc)| ANTI/VITA| | |

Choanal Atresia| LEVOTHYROXINE SODIUM| | |

TGA +/- DORV| FLONASE| | |

Cleft Lip +/- Palate| | ATENOLOL| |

Intestinal Atresia/Stenosis| | EPHEDRA| |

VSDs (Excludes VSDavc)| | BUTALBITAL| |

Esoph Atresia +/- TEF| | FLONASE| |

Cleft Lip +/- Palate| | | LABETOLOL|

Esoph Atresia +/- TEF| | | ATENOLOL|

VSDs (Excludes VSDavc)| | | ALBUTEROL SULFATE|

TOF +/- PA, DORV -TGA| | | BUTALBITAL|

Choanal Atresia| | | LEVOTHYROXINE SODIUM|

;

 

proc sort data=test2; by analysis component; run;

 

proc sql;

create table test2Matchtotal as

select a.*

from test2 as a inner join

test1 as b on a.Analysis=b.Analysis and (a.class=b.product or a.component=b.product or a.product=b.product);

quit;

 

 

1 ACCEPTED SOLUTION

Accepted Solutions
ballardw
Super User

The values are duplicated because this:

(a.class=b.product or a.component=b.product or a.product=b.product);

creates a match for potentially 3 conditions but the requested output (a.*) doesn't change the result selected

 

If you don't want duplicated results one approach is the distinct predicate.

 

Select distinct a.*

View solution in original post

3 REPLIES 3
Reeza
Super User

Post your code into the code editor. 

And format and comment it. 

 

ballardw
Super User

The values are duplicated because this:

(a.class=b.product or a.component=b.product or a.product=b.product);

creates a match for potentially 3 conditions but the requested output (a.*) doesn't change the result selected

 

If you don't want duplicated results one approach is the distinct predicate.

 

Select distinct a.*

ybz12003
Rhodochrosite | Level 12


Cool !!!

sas-innovate-2024.png

Join us for SAS Innovate April 16-19 at the Aria in Las Vegas. Bring the team and save big with our group pricing for a limited time only.

Pre-conference courses and tutorials are filling up fast and are always a sellout. Register today to reserve your seat.

 

Register now!

What is Bayesian Analysis?

Learn the difference between classical and Bayesian statistical approaches and see a few PROC examples to perform Bayesian analysis in this video.

Find more tutorials on the SAS Users YouTube channel.

Click image to register for webinarClick image to register for webinar

Classroom Training Available!

Select SAS Training centers are offering in-person courses. View upcoming courses for:

View all other training opportunities.

Discussion stats
  • 3 replies
  • 662 views
  • 1 like
  • 3 in conversation