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robertrao
Quartz | Level 8

I have code1=146

what is the meaning of "&&code&j

when j=1 in a loop

How do I resolve it???

Thanks

1 ACCEPTED SOLUTION

Accepted Solutions
ballardw
Super User

With a loop SAS is looking for a series of macro variables &code1 &code2 &code3. The starting && tells SAS that something has to resolve first before looking for the actual value of the variable. So &   &code&j => &code1 .

And in your example when j=1 &&code&j should have a value of 146.

If you want to see the value:

%put &&code&j; shows the value in the log.

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2 REPLIES 2
slchen
Lapis Lazuli | Level 10

&&code&j  first resolve to &code1, then &code1 resolve to 146.

ballardw
Super User

With a loop SAS is looking for a series of macro variables &code1 &code2 &code3. The starting && tells SAS that something has to resolve first before looking for the actual value of the variable. So &   &code&j => &code1 .

And in your example when j=1 &&code&j should have a value of 146.

If you want to see the value:

%put &&code&j; shows the value in the log.

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