BookmarkSubscribeRSS Feed
🔒 This topic is solved and locked. Need further help from the community? Please sign in and ask a new question.
sreeram
Fluorite | Level 6
i have a CHARACTER VARIABLE in which dates are partially written, ie. '2007-09', '2010-10' etc. Now i have to find the last date of the month ie. in 2007-09, last date in the month 09 added to the new variable representing like 2007-09-30 etc. Can some one help me in doing this. Message was edited by: sreeram
1 ACCEPTED SOLUTION

Accepted Solutions
sreeram
Fluorite | Level 6

Editor's Note:  Thanks to sreeram for showing the optional fourth argument to the INTNX function that allows you to specify the alignment when incrementing the date.  To find the last day of the month, the alignment should be set to 'END' or 'E'.  This will increment the starting date so that it falls on the last day of the month. 

Instead of concatenating the '01' to the starting value, the ANYDTDTE informat can be used to create a SAS date from just the year and month.  The resulting SAS date will default to the first day of the month.  This slight modification has been made to sreeram's original code.


 

data a;     
aeendtc1='2007-09';
aeendtc2=input(aeendtc1,anydtdte7.);
lastDay=intnx ('month',aeendtc2,0,'E');
mydate=put(lastday,yymmdd10.);
run;
proc print;
  format aeendtc2 lastday yymmddd10.;
run;


aeendtc1=strip(aeendtc)||"-01";
aeendtc2=input(aeendtc1,yymmdd10.);
lastDay=intnx ('month',aeendtc2,0,'E');
mydate=put(lastday,yymmdd10.);

 

View solution in original post

3 REPLIES 3
sreeram
Fluorite | Level 6

Editor's Note:  Thanks to sreeram for showing the optional fourth argument to the INTNX function that allows you to specify the alignment when incrementing the date.  To find the last day of the month, the alignment should be set to 'END' or 'E'.  This will increment the starting date so that it falls on the last day of the month. 

Instead of concatenating the '01' to the starting value, the ANYDTDTE informat can be used to create a SAS date from just the year and month.  The resulting SAS date will default to the first day of the month.  This slight modification has been made to sreeram's original code.


 

data a;     
aeendtc1='2007-09';
aeendtc2=input(aeendtc1,anydtdte7.);
lastDay=intnx ('month',aeendtc2,0,'E');
mydate=put(lastday,yymmdd10.);
run;
proc print;
  format aeendtc2 lastday yymmddd10.;
run;


aeendtc1=strip(aeendtc)||"-01";
aeendtc2=input(aeendtc1,yymmdd10.);
lastDay=intnx ('month',aeendtc2,0,'E');
mydate=put(lastday,yymmdd10.);

 

SPR
Quartz | Level 8 SPR
Quartz | Level 8
Hello Sreeram,
[pre]
This is a solution:
data i;
input dt0 $;
datalines;
2007-09
2007-10
run;
data r;
set i;
dt=INPUT(CATS(dt0,"-01"),ANYDTDTE10.);
dr=INTNX("MONTH",dt,1,"BEGINNING")-1;
format dt date7. dr YYMMDD10.;
run;
[/pre]
Sincerely,
SPR
Peter_C
Rhodochrosite | Level 12
> i have a CHARACTER VARIABLE in which dates are
> partially written, ie. '2007-09', '2010-10' etc. Now
> i have to find the last date of the month ie. in
> 2007-09, last date in the month 09 added to the new
> variable representing like 2007-09-30 etc. Can some
> one help me in doing this.
>

intnx( 'month', input( cats(your_char_var, '-01'), yymmdd10.), 0, 'ending' )

hackathon24-white-horiz.png

2025 SAS Hackathon: There is still time!

Good news: We've extended SAS Hackathon registration until Sept. 12, so you still have time to be part of our biggest event yet – our five-year anniversary!

Register Now

What is Bayesian Analysis?

Learn the difference between classical and Bayesian statistical approaches and see a few PROC examples to perform Bayesian analysis in this video.

Find more tutorials on the SAS Users YouTube channel.

SAS Training: Just a Click Away

 Ready to level-up your skills? Choose your own adventure.

Browse our catalog!

Discussion stats
  • 3 replies
  • 132670 views
  • 4 likes
  • 3 in conversation