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hadesmr
Calcite | Level 5

id x

1 2

2 3

3 5

4 8

5 9

6 8

hi, i have sample dataset like above. i want to create a new variable y, such that,

if id = 1, then y = x;

else y(t)= y(t-1) * 2.

in this case:

y(1) = x(1) =  2

y(2) = y(1) *2 = 2*2 = 4

y(3) =y(2) *2 = 4*2 = 8

y(4) =y(3) *2 = 8*2 = 16

y(5) = y(4) *2 = 16*2 = 32

y(6) = y(5) *2 = 32*2 = 64

i am wondering if there is any function to achieve it? looks like lag can't do it.

thanks a lot for your help!

1 ACCEPTED SOLUTION

Accepted Solutions
Slash
Quartz | Level 8

Hi, you can try this method. You are right, LAG function can't do it.

data test;

input id x;

retain temp;

if id=1 then do;

  y=x;

  temp=y;

end;

if id ne 1 then do;

  y=temp*2;

  temp=y;

end;

drop temp;

cards;

1 2

2 3

3 5

4 8

5 9

6 8

;

run;

View solution in original post

5 REPLIES 5
Slash
Quartz | Level 8

Hi, you can try this method. You are right, LAG function can't do it.

data test;

input id x;

retain temp;

if id=1 then do;

  y=x;

  temp=y;

end;

if id ne 1 then do;

  y=temp*2;

  temp=y;

end;

drop temp;

cards;

1 2

2 3

3 5

4 8

5 9

6 8

;

run;

hadesmr
Calcite | Level 5

Smart! thank you!

Keith
Obsidian | Level 7

You can simplify the code a bit.

data test;

input id x;

retain y;

y=ifn(id=1,x,y*2);

cards;

1 2

2 3

3 5

4 8

5 9

6 8

;

run;

hadesmr
Calcite | Level 5

Thanks Keith, works better!

Slash
Quartz | Level 8

Year, this is easier.

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