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AminB
Fluorite | Level 6

The simplest answer is a combination of 2 answers:

data have;

input Subject $ Value1    value2 value3  value4;

datalines;

10001     3        4       5       8

10007     4        6       4       9

10009     4        9      10       3

run;
data need;

   set have;

   value = max(of value1 - value4);

run;

the dataset NEED will look as follows:

10001     3        4       5       8     8

10007     4        6       4       9     9

10009     4        9      10       3     10

Message was edited by: Amin Bardai

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