Greetings Community,
I have this text variable that captures the dates
03/15/2015 |
3/17/2016 |
Some with leading zeros (for Jan to Sep), and some without the leading zeros. I need to convert it into a date format.
I tried this code:
Correct_date = input(text_date,ddmmyy10.) ;
format Correct_date YYMMDD10.;
I received this error:
NOTE: Invalid argument to function INPUT at line 30 column 15.
Sure thing 🙂
data have;
text_date="03/15/2015";output;
text_date="3/17/2016";output;
text_date="05/0/2015";output;
text_date="11/0/2016";output;
run;
data want;
set have;
text_date=tranwrd(text_date, '/0/', '/1/');
Correct_date = input(text_date,mmddyy10.);
format Correct_date mmddyy10.;
run;
You almost have it. You have to use the MMDDYY10. informat and not the DDMMYY10. Like this
data have;
text_date="03/15/2015";output;
text_date="3/17/2016";output;
run;
data want;
set have;
Correct_date = input(text_date,mmddyy10.);
format Correct_date mmddyy10.;
run;
Thank you draycut for the code. I found where the problem is. I have some dates with month and year, but that have 0 for the day as follows:
05/0/2015
11/0/2016
The converted dates with your code are missings. I need to convert them to the beginning of the month, if the day is 0 as follows:
05/01/2015
11/01/2016
Any idea how that can be done?
Thanks!
Sure thing 🙂
data have;
text_date="03/15/2015";output;
text_date="3/17/2016";output;
text_date="05/0/2015";output;
text_date="11/0/2016";output;
run;
data want;
set have;
text_date=tranwrd(text_date, '/0/', '/1/');
Correct_date = input(text_date,mmddyy10.);
format Correct_date mmddyy10.;
run;
Are you ready for the spotlight? We're accepting content ideas for SAS Innovate 2025 to be held May 6-9 in Orlando, FL. The call is open until September 25. Read more here about why you should contribute and what is in it for you!
Learn the difference between classical and Bayesian statistical approaches and see a few PROC examples to perform Bayesian analysis in this video.
Find more tutorials on the SAS Users YouTube channel.