Hi.. I am trying to come up with a SAS code that can identify all letter values among all variables. For example, I have a dataset that have 3 CHAR variables (var1 - var3):
var1 var2 var3
01 10 M9
02 3M 00
N 09
07 18 11
How can I just extract all the letter values (values that have letter in them)?
var1 var2 var3
N 3M M9
or, even better, how I can have output like this?
special_value
N
3M
M9
data have;
input (var1 var2 var3) ($);
cards;
01 10 M9
02 3M 00
N . 09
07 18 11
;
data want;
set have;
array t var1-var3;
do i=1 to dim(t);
if anyalpha(t(i)) then
do;
want=t(i);
output;
end;
end;
keep want;
run;
Thanks for the quick reply!
If I have 100+ variables there, can I do this?
%let varlist = %str(var1 ... var1000); (?)
data want;
set have;
array t &varlist.;
do i=1 to dim(t);
if anyalpha(t(i)) then
do;
want=t(i);
output;
end;
end;
keep want;
run;
Sure.
I wonder why you need to quote though with %str
I believe just
%let arraylist=var1 var2 var3 varN;
should work fine
Macro quoting is not needed in this instance.
Thank you! Let me try this! 😃
Alternatively with regular expressions
data want(where=(newvars ne ''));
set have;
array vars(*) $ var1 var2 var3;
do i = 1 to dim(vars);
newvars=ifc(prxmatch('m/[A-Z]/',strip(vars(i))),strip(vars(i)),'') ;
output;
end;
run;
Thanks! 😃
Sure.. how can I do that?
Let's build on your earlier program:
%let varlist = var1 ... var1000;
data want;
set have;
array t &varlist.;
do i=1 to dim(t);
if anyalpha(t{i}) then do;
want=t{i};
recno = _n_;
varname = vname(t{i}) ;
output;
end;
end;
keep want recno varname;
run;
Are you ready for the spotlight? We're accepting content ideas for SAS Innovate 2025 to be held May 6-9 in Orlando, FL. The call is open until September 25. Read more here about why you should contribute and what is in it for you!
Learn the difference between classical and Bayesian statistical approaches and see a few PROC examples to perform Bayesian analysis in this video.
Find more tutorials on the SAS Users YouTube channel.