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MCB
Calcite | Level 5 MCB
Calcite | Level 5


Hi,

I have this data set: 1 parent with 2 children, both children appears on each case. case nr 2 repeat itself three tims for child nr 465. I need to create a variable (counter) which counts the children by the parent-ID. The expected results are dispayed on the right column "wanted counter". Can anyone sujest how to solve it? thanks.

obsCASEID-parentID-childWanted counter

1

1101111
21104552
32101111
4210

455

2
52104552
62104552
1 ACCEPTED SOLUTION

Accepted Solutions
Haikuo
Onyx | Level 15

Give the data as is, and with the assumption that the data is sorted or at least clustered:

data have;

input CASE    ID_parent    ID_child ;

cards;

1    10    111   

1    10    455   

2    10    111   

2    10    455   

2    10    455   

2    10    455   

;

data want;

set have;

by case id_parent Id_child notsorted;

if first.case then call missing (count);

   count+first.id_child;

run;

proc print;run;

Haikuo

View solution in original post

3 REPLIES 3
Haikuo
Onyx | Level 15

Give the data as is, and with the assumption that the data is sorted or at least clustered:

data have;

input CASE    ID_parent    ID_child ;

cards;

1    10    111   

1    10    455   

2    10    111   

2    10    455   

2    10    455   

2    10    455   

;

data want;

set have;

by case id_parent Id_child notsorted;

if first.case then call missing (count);

   count+first.id_child;

run;

proc print;run;

Haikuo

MCB
Calcite | Level 5 MCB
Calcite | Level 5

Thanks! I will try it!

DanielSantos
Barite | Level 11

Using lag, and deriving from Mike's simplified code here: https://communities.sas.com/message/137090#137090


data WANT;

set HAVE;

    retain WANTED;

    WANTED=sum(WANTED*(lag(CASE) = CASE),(lag(ID_child) ^= ID_child));

run;


More on the LAG function here:

http://support.sas.com/documentation/cdl/en/lrdict/64316/HTML/default/a000212547.htm


Cheers from Portugal.

Daniel Santos @ www.cgd.pt

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