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jl1005
Obsidian | Level 7

Hi,

 

In my data, I have multiple rows for one person and I'd like to combine all the rows into one unique row while summing the values. For example:

 

combine.JPG

Where year_id and bat_id are equal, I would like to combine the rows and sum the column values. So for 2015, I would just want one row with values:

 82 for G, 232 for AB, and so one. What procedure is best able to do this, or could it be done in the data step?

 

Thank you,

 

Justin

1 ACCEPTED SOLUTION

Accepted Solutions
Jagadishkatam
Amethyst | Level 16

you could try the proc means

 

data have;
input year_id 	bat_id$	g	ab	r	h	_2b;
cards;
2015	almoa001	51	178	30	47	9
2015	almoa001	31	54	6	11	3
2014	almoa001	32	98	9	26	5
2014	almoa001	27	106	10	21	5
;


proc means data=have nway;
class year_id bat_id;
var g ab r h _2b;
output out=sums sum=/autoname;
run;

 

 

Thanks,
Jag

View solution in original post

3 REPLIES 3
Jagadishkatam
Amethyst | Level 16

you could try the proc means

 

data have;
input year_id 	bat_id$	g	ab	r	h	_2b;
cards;
2015	almoa001	51	178	30	47	9
2015	almoa001	31	54	6	11	3
2014	almoa001	32	98	9	26	5
2014	almoa001	27	106	10	21	5
;


proc means data=have nway;
class year_id bat_id;
var g ab r h _2b;
output out=sums sum=/autoname;
run;

 

 

Thanks,
Jag
Jagadishkatam
Amethyst | Level 16

alternatively proc sql

 

proc sql;
create table want as select year_id, bat_id,sum(g) as g, sum(ab) as ab, sum(r) as r, sum(h) as h, sum(_2b) as _2b
from have group by year_id,bat_id;
quit;
Thanks,
Jag
ballardw
Super User

If you use @Jagadishkatam's Proc Means solution with Sum= instead of Sum= / autoname then the variable names would stay unchanged if that would be the preferred behavior.

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