I have a table wchich looks like below:
year elec ngas petro transp
1993 0.328962596541413 0.0333333333333333 0.0294741106255071 0.0312981997615055
1994 0.32131918710743 0.0357852882703777 0.0280891133921987 0.0296270473156796
1995 0.312689346078104 0.0301204819277108 0.0299476941480979 0.0307595385921147
1996 0.302492954358166 0.0296846011131725 0.0306720643123235 0.0315941372524655
1997 0.297555088719812 0.037109375 0.0313930047898444 0.0324508531293975
1998 0.279078628962933 0.0390455531453362 0.0324409310705472 0.0333306670536662
1999 0.269449037043657 0.0390946502057613 0.0338084853707251 0.0342346177942214
2000 0.268587236213135 0.0389105058365759 0.0354842304721889 0.0367621612481076
2001 0.267152131952974 0.0426829268292683 0.0346861443472607 0.036119401007415
2002 0.25010602338106 0.041501976284585 0.0347417788989821 0.0361976486955247
2003 0.249007386555198 0.04 0.034782939573557 0.0362781339184914
I want to automatically generate the following vectors:
hhd_nrg_coeff_order = {'elec', 'ngas', 'petro', 'transp'};
hhd_nrg_coeffs_93 = {0.328962596541413 , 0.0333333333333333, 0.0294741106255071 , 0.0312981997615055};
hhd_nrg_coeffs_94 = {0.32131918710743 , 0.0357852882703777, 0.0280891133921987, 0.0296270473156796};
....
hhd_nrg_coeffs_03 = {0.249007386555198 0.04 0.034782939573557 0.0362781339184914}
is there any way to generate it automatically in SAS.
because I have more data till 2010 so it is gana be nasty in the code.
Thanks
Sure, but I'd recommend using a matrix and nidexing the rows instead of creating separate row vectors, one for each row of the data.
Here's what I'd do (this code has not been run...might have syntax errors). To get the var names, use
use MyData;
read all var _NUM_ into X[colname=hhd_nrg_coeff_order];
close MyData;
That sets the vector hhd_nrg_coeff_order to {"year"..."transp"};
Then extract the first column and convert it to a character vector:
y = X[,1];
year = char(y);
X = X[,2:ncol(X)]; /* strip off first col */
hhd_nrg_coeff_order = hhd_nrg_coeff_order[,2:ncol(X)];
Now you can use a trick that I recently blogged about where you can assign the YEAR variable to be the row index.
The blog is Access rows or columns of a matrix by names - The DO Loop
It looks like this:
mattrib X[rowname=year];
You can now refer to each row by using the name of the row. For example:
DataFor1997 = X['1997', ];
If you need a loop, you can use
do i = 1 to nrow(year);
z = X[year, ]; /* get i_th row */
/* do stuff...*/
end;
Of course, you can also omit the MATTRIB statement and just index the rows by i, and use year in case you need the value of YEAR for that observation.
Thank you so very mcuh. It is a big help.
Are you ready for the spotlight? We're accepting content ideas for SAS Innovate 2025 to be held May 6-9 in Orlando, FL. The call is open until September 25. Read more here about why you should contribute and what is in it for you!
Learn how to run multiple linear regression models with and without interactions, presented by SAS user Alex Chaplin.
Find more tutorials on the SAS Users YouTube channel.