BookmarkSubscribeRSS Feed
🔒 This topic is solved and locked. Need further help from the community? Please sign in and ask a new question.
MDaniel
Obsidian | Level 7

Is there a way to write the 5th line below so that it works (while keeping it within a single expression / single line) ?

More generally, how can a vector be initiated by specifying formulas instead of values for each element?

 

proc iml;
	x = j(3,2,.);
	do i = 1 to nrow(x);
		/*this doesn't work*/
		x[i,] = { i 0 };

		/*this does work, but it's an extra line */
		x[i,1] = i;
		x[i,2] = 0;
	end;
quit
1 ACCEPTED SOLUTION

Accepted Solutions
Rick_SAS
SAS Super FREQ

The direct answer to your question is to use the horizontal concatenation operator (||)

x[i,] = i || 0;

as described in the article "How to build a vector from expressions."

 

Of course, for this example, you don't need a loop at all:

proc iml;
x1 = T( 1:3 );
x2 = j(nrow(x1), 1, 0);
x = x1 || x2;

View solution in original post

1 REPLY 1
Rick_SAS
SAS Super FREQ

The direct answer to your question is to use the horizontal concatenation operator (||)

x[i,] = i || 0;

as described in the article "How to build a vector from expressions."

 

Of course, for this example, you don't need a loop at all:

proc iml;
x1 = T( 1:3 );
x2 = j(nrow(x1), 1, 0);
x = x1 || x2;

sas-innovate-2026-white.png



April 27 – 30 | Gaylord Texan | Grapevine, Texas

Registration is open

Walk in ready to learn. Walk out ready to deliver. This is the data and AI conference you can't afford to miss.
Register now and lock in 2025 pricing—just $495!

Register now

From The DO Loop
Want more? Visit our blog for more articles like these.
Discussion stats
  • 1 reply
  • 1414 views
  • 0 likes
  • 2 in conversation