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Posted 01-18-2017 02:07 PM
(3735 views)

How can we apply IF/THEN/ELSE statement to each element in a n*m matrix so that the result is also a n*m matrix of TRUE/FALSE?

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Could you provide an example?

To get a boolean (0 or 1) matrix, just use a logical expression with a matrix:

```
proc iml;
x = {1 2,
1 3,
2 4};
b = (x > 2);
print b;
```

The IF-THEN/ELSE statement works on a scalar quantity. The ANY function and ALL function can be used with the IF-THEN statement to make logical decisions. For example:

```
if any(x) > 3 then print "Some element > 3";
else print "No element > 3";
if all(x) > 0 then print "All elements > 0";
else print "Some element <= 0";
```

For more information, see "IF-THEN logic with matrix expressions."

3 REPLIES 3

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Could you provide an example?

To get a boolean (0 or 1) matrix, just use a logical expression with a matrix:

```
proc iml;
x = {1 2,
1 3,
2 4};
b = (x > 2);
print b;
```

The IF-THEN/ELSE statement works on a scalar quantity. The ANY function and ALL function can be used with the IF-THEN statement to make logical decisions. For example:

```
if any(x) > 3 then print "Some element > 3";
else print "No element > 3";
if all(x) > 0 then print "All elements > 0";
else print "Some element <= 0";
```

For more information, see "IF-THEN logic with matrix expressions."

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```
Given a matrix x below, I would like to have a resultant matrix y having 1 for each element of x<0 else 0:
proc iml;
```

x = {1 2,

1 -3,

2 4};

IF x<0 THEN y=1;

ELSE y=0;

print y;

Resultant matrix should be:

y= {0 0,

0 1,

0 0}

The result however is a scalar y=0

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As I explained in my previous response, don't use the IF-THEN statement. Just create the binary matrix:

```
proc iml;
x = {1 2,
1 -3,
2 4};
y = (x<0);
print y;
```

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