IML if-then

[shkim]

Hi,

I have already complete macro program code that computes pe and ps. (Attachments: macro test)
but i don't know how to code

when  , if pe < 0.05 then I = l-1, if ps < 0.05 then m = m + 1, and pe and ps must be repeated until both are greater than 0.05.

**ex data**

proc iml;
ze_0={1,2,3};
zs_0{1,3,5};
ze_1={2,3,4};
zs_1={2,4,2};
ze_2={1,3,2};
zs_2={2,5,4};
quit;

pe=#{max(ze_i[l,1],zs_i[m,1])>=ze_0[l,1]}/nb
ps=#{max(zs_i[l,1],zs_i[m,1])>=zs_0[m,1]}/nb

l=3 to 1;

m=1 to 3;

i=1,2
nb=2;

[PaigeMiller]

IF statements in IML work the same as IF statements anywhere else. So it's not clear to me exactly what your problem is. Can you be much more specific?

[shkim]

I posted the code in the attachment,
I'm not sure of the last part of the macro code.

I don't know how to code for this part.

- if pe<0.05 then l = l-1 

  if ps <0.05 then m = m + 1  , and pe and ps must be calculated until both pe and ps are greater than 0.05..

[PaigeMiller]

And what happens when you execute this code? 

Show us the SASLOG of the relevant parts. Use the {i} button and paste the SASLOG of the relevant parts into the {i} window.

[shkim]

data ze_0;
input COL1 @@;
cards;
  0.16013 
  0.32026 
  0.80064 
  0.64051 
  0.64051 

run;

data zs_0;
input COL1 @@;
cards;
-0.16013
-0.48038
0.32026
0.48038
0.80064
run;

data ze_1;
input COL1 @@;
cards;
-0.16013
-0.16013
-0.16013
0.00000
0.32026
run;

data zs_1;
input COL1 @@;
cards;
-0.64051
-1.28103
-0.80064
-0.80064
-0.32026
run;

data ze_2;
input COL1 @@;
cards;
1.92154
2.40192
2.40192
0.96077
1.92154
run;

data zs_2;
input COL1 @@;
cards;
1.60128
1.44115
0.48038
1.12090
2.08167
run;

data ze_3;
input COL1 @@;
cards;
0.32026
1.44115
1.76141
1.76141
2.08167
run;

data zs_3;
input COL1 @@;
cards;
0.16013
-1.44115
-0.16013
-0.48038
0.32026
run;

data ze_4;
input COL1 @@;
cards;
0.00000
0.00000
0.96077
0.64051
0.64051
run;

data zs_4;
input COL1 @@;
cards;
-0.80064
-1.60128
-1.12090
-1.60128
-0.64051
run;

data ze_5;
input COL1 @@;
cards;
-1.28103
-0.80064
-0.48038
-0.64051
-0.96077
run;

data zs_5;
input COL1 @@;
cards;
-1.60128
-0.48038
0.48038
0.48038
0.16013
run;

When you run this data set and attachment macros (new attachments)
There is no error, but the desired result is different.

% let l = 5;
% let m = 1;
% test (nb = 5, l = & l, m = & m);

This is result in pe = 0.6 ps = 0.8.

Since pe < 0.7,

Next is   

% let l = 4; % let m = 1; % test (nb = 5, l = & l, m = & m);
This should be done.

With such a routine, when l = 3 and m = 1, pe and ps are both greater than 0.7 for the first time.

However, if the macro aaa is executed, the value of l = 4 and m = 2 appears, so i don't know why the value is wrong.