NOTICE: code changed for fixing a problem. Sorry ! OK. I misunderstood. data want; array col(5) (1 4 5 5 4); temp1=largest(1,of col(*)); do i=1 to dim(col); if col{i}=temp1 then do; col{i}=.;index_of_1nd=i; value_1=vname(col(index_of_1nd)); leave; end; end; temp2=largest(1,of col(*)); do i=1 to dim(col); if col{i}=temp2 then do; index_of_2nd=i; value_2=vname(col(index_of_2nd)); leave; /*<--------*/ end; end; drop i temp1 temp2; run;
KSsharp: it works ! thank you very much. Can you please briefly explain you code, of course if you have time 🙂
Actually , It could be rewrited by WHICHN().
I think it is more readable for you .
data want;
array col(5) (1 4 5 5 4);
temp=max(of col(*));
idx=whichn(temp,of col(*));
col{idx}=.;
index_of_1nd=idx;
value_1=vname(col(index_of_1nd));
temp=max(of col(*));
idx=whichn(temp,of col(*));
col{idx}=.;
index_of_2nd=idx;
value_2=vname(col(index_of_2nd));
drop temp idx;
run;
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