NOTICE: code changed for fixing a problem. Sorry ! OK. I misunderstood. data want; array col(5) (1 4 5 5 4); temp1=largest(1,of col(*)); do i=1 to dim(col); if col{i}=temp1 then do; col{i}=.;index_of_1nd=i; value_1=vname(col(index_of_1nd)); leave; end; end; temp2=largest(1,of col(*)); do i=1 to dim(col); if col{i}=temp2 then do; index_of_2nd=i; value_2=vname(col(index_of_2nd)); leave; /*<--------*/ end; end; drop i temp1 temp2; run;
KSsharp: it works ! thank you very much. Can you please briefly explain you code, of course if you have time 🙂
Actually , It could be rewrited by WHICHN().
I think it is more readable for you .
data want;
array col(5) (1 4 5 5 4);
temp=max(of col(*));
idx=whichn(temp,of col(*));
col{idx}=.;
index_of_1nd=idx;
value_1=vname(col(index_of_1nd));
temp=max(of col(*));
idx=whichn(temp,of col(*));
col{idx}=.;
index_of_2nd=idx;
value_2=vname(col(index_of_2nd));
drop temp idx;
run;
Join us for SAS Innovate April 16-19 at the Aria in Las Vegas. Bring the team and save big with our group pricing for a limited time only.
Pre-conference courses and tutorials are filling up fast and are always a sellout. Register today to reserve your seat.
What’s the difference between SAS Enterprise Guide and SAS Studio? How are they similar? Just ask SAS’ Danny Modlin.
Find more tutorials on the SAS Users YouTube channel.