I have the following data set:
Id | DOB | Type |
11 | 1/5/1998 | Second |
22 | 6/8/1987 | Third |
33 | 5/3/2012 | Fourth |
33 | 6/10/1945 | First |
22 | 3/2/1986 | Fifth |
44 | 1/1/1992 | First |
I need to pull the duplicates by ID and DOB.
I need the following data to be made:
Id | DOB | Type |
22 | 6/8/1987 | Third |
22 | 3/2/1986 | Fifth |
33 | 5/3/2012 | Fourth |
33 | 6/10/1945 | First |
Can you please help?
data have;
input Id DOB :mmddyy10. Type $;
format dob mmddyy10.;
cards;
11 1/5/1998 Second
22 6/8/1987 Third
33 5/3/2012 Fourth
33 6/10/1945 First
22 3/2/1986 Fifth
44 1/1/1992 First
;
proc sql;
create table want as
select *
from have
group by id
having count(id)>1;
quit;
I don't think your result appropriates two variables as ID and DOB(different) dobs are not duplicates rather the combination is unique. If the above doesn't meet your requirement, plz clarify
I apologize. I do need it to have the result I stated.
Same IDs attached to different DOBs.
No worries and thanks. The above code should work for your requirement.
Or just with proc sort
PROC SORT DATA=have OUT=want NOUNIQUEKEY;
BY id;
RUN;
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