I have a id and date column and I want to find out if the id had a second within 2 weeks(14 days);
id date
1 07JAN2018
2 28MAR2018
3 14FEB2018
1 28JAN2018
2 11APR2018
3 24FEB2018
..
..
..
OUTPUT:
id date SEEN within 2 weeks(14 days from the first date)
1 07JAN2018 No
2 28MAR2018 yes
3 14FEB2018 yes
1 28JAN2018 .
2 11APR2018 .
3 24FEB2018 .
.
Please show what you expect for output for your example input.
"Week" is a somewhat slippery concept. By within two weeks do you mean 14 days, do you have any rules about "workdays" "weekdays", which day of a week starts a week.
And the ever popular is your date variable actually a SAS date valued variable?
Below should work. Please post next time your sample data via a working SAS data step as I've done below.
data have;
input id date :date9.;
format date date9.;
datalines;
1 07JAN2018
2 28MAR2018
3 14FEB2018
1 28JAN2018
2 11APR2018
3 24FEB2018
;
run;
proc sql;
create table want as
select
o.*,
case
when
(select i.date from have i
where i.id=o.id
and i.date between o.date+1 and o.date+14
) ne . then 'Yes'
else 'No'
end as YesNo length=3
from have o
;
quit;
data have;
input id date :date9.;
format date date9.;
datalines;
1 07JAN2018
2 28MAR2018
3 14FEB2018
1 28JAN2018
2 11APR2018
3 24FEB2018
;
run;
data temp;
set have;
if id=1 then group+1;
run;
proc sort data=temp;
by id descending group;
run;
data temp;
set temp;
dif=dif(date);
if id=lag(id) and abs(dif)<=14 then flag='yes';
else flag='no';
run;
proc sort data=temp out=want;
by group id;
run;
proc print;run;
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