Hi,
suppose I have stock price data of the follwing form (and I have many stocks but for simplicity here will include only 2):
|
date |
Stock1_price |
Stock2_price |
|
20/1/2015 |
20 |
6 |
|
19/1/2015 |
10 |
3 |
|
18/1/2015 |
5 |
1 |
What I would like to obtain is the stock returns for all of my stocks:
|
date |
Stock1_return |
Stock2_return |
|
20/1/2015 |
1 |
1 |
|
19/1/2015 |
1 |
1.5 |
|
18/1/2015 |
. |
. |
If I had only one (or a small number) stock I would just create a new colum "lag_price" and then calculate the return as (price-lag_price)/ lag_price, but in the case of many stocks its not practical...
Thank you!
It would be very easy for IML. Do you want IML code?
OR you could use array.
data have;
input date : ddmmyy10. Stock1_price Stock2_price;
format date ddmmyy10.;
cards;
20/1/2015
20
6
19/1/2015
10
3
18/1/2015
5
1
;
run;
proc sort data=have;by date;run;
data want;
set have;
array x{*} return1-return2;
array y{*} Stock1_price Stock2_price;
do i=1 to dim(x);
x{i}=dif(y{i})/lag(y{i});
end;
run;
proc sort data=want;by descending date;run;
It would be very easy for IML. Do you want IML code?
OR you could use array.
data have;
input date : ddmmyy10. Stock1_price Stock2_price;
format date ddmmyy10.;
cards;
20/1/2015
20
6
19/1/2015
10
3
18/1/2015
5
1
;
run;
proc sort data=have;by date;run;
data want;
set have;
array x{*} return1-return2;
array y{*} Stock1_price Stock2_price;
do i=1 to dim(x);
x{i}=dif(y{i})/lag(y{i});
end;
run;
proc sort data=want;by descending date;run;
Consider transposing your data from wide to long.
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