I have some code below with the @ sign that devides the data set into two datasets; first and second (using the @ sign):
data first second; INPUT x y @; OUTPUT first; INPUT x y; OUTPUT second; DATALINES; 1 2 3 4 9 10 5 6 7 8 ; PROC PRINT data=first; Title 'first'; RUN; PROC PRINT data=second; Title 'second'; RUN;
When I replace the @ sign with @@ I am getting the same result but I was assuming I would not. I am wondering why the two different code produce the same output. Thank you for any advise.
You defeat the functionality of @ and @@ by including two input statements. Try the following:
data first_a second_a;
INPUT x y @;
if mod(_n_,2) then OUTPUT first_a;
else OUTPUT second_a;
DATALINES;
1 2 3 4 5 6
7 8 9 10 11 12
;
data first_b second_b;
INPUT x y @@;
if mod(_n_,2) then OUTPUT first_b;
else OUTPUT second_b;
DATALINES;
1 2 3 4 5 6
7 8 9 10 11 12
;
Art, CEO, AnalystFinder.com
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