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ilikesas
Barite | Level 11

I have the following:

 

data have;
input num x1 x2 x3;
datalines;
1 . . .
2 . . .
3 . . .
;
run;

 

suppose i want to make a multiplication table (pseudo code)

data want;

set have;

do i=1 to 3

  x&i = number*i;

end

run;

 

Basically, the variables x1-x3 contain in them information, namely, the multiplication factor, so I want using a loop to "assemble" the variable name.

 

Thank you 

1 ACCEPTED SOLUTION

Accepted Solutions
VDD
Ammonite | Level 13 VDD
Ammonite | Level 13
data have;
input num x1 x2 x3;
datalines;
1 . . .
2 . . .
3 . . . 
;
run;
data want;
set have;
array x{*} $ x1-x3;
do i=1 to 3;
  x[i] = num*i;
  if i = 3 then output;
end;
run;

View solution in original post

2 REPLIES 2
VDD
Ammonite | Level 13 VDD
Ammonite | Level 13
data have;
input num x1 x2 x3;
datalines;
1 . . .
2 . . .
3 . . . 
;
run;
data want;
set have;
array x{*} $ x1-x3;
do i=1 to 3;
  x[i] = num*i;
  if i = 3 then output;
end;
run;
Tom
Super User Tom
Super User

@VDD Why did you include the OUTPUT statement?

 

Don't tell SAS that the array has character variables when they are already defined as numeric should cause an error.  Also note there is no need to tell SAS how many elements are in the array when you have listed the names.  It will just count them.

array x x1-x3;

and you don't have to count them either, use the DIM() function.

do i=1 to dim(x);

 

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