Hi, I would like to add on to this code so that the value of the last measurement according to the "date" column in the "measurement" column is divided by the lowest value recorded in the measurement column and the result forms a new column. The current working code adds a column that subtracts the initial measurements from the other measurements in the "measurement" column if the "subject", "type" and "procedure" columns match.
data have;
input Subject Type Date $ 5-12 Procedure $ 15-22 Measurement;
datalines;
500 Initial 15 AUG 2017 Invasive 20
500 Initial 18 SEPT 2018 Surface 35
500 Followup 12 SEPT 2018 Invasive 54
428 Followup 2 JUL 2019 Outer 29
765 Seventh 3 JUL 2018 Other 13
500 Followup 6 NOV 2018 Surface 98
428 Initial 23 FEB 2018 Outer 10
765 Initial 20 AUG 2019 Other 19
610 Third 21 AUG 2018 Invasive 66
610 Initial 27 Mar 2018 Invasive 17
;
data want (drop=rc _Measurement);
if _N_ = 1 then do;
declare hash h (dataset : "have (rename=(Measurement=_Measurement) where=(Type='Initial'))");
h.definekey ('Subject');
h.definedata ('_Measurement');
h.definedone();
end;
set have;
_Measurement=.;
if Type ne 'Initial' then rc = h.find();
NewMeasurement = ifn(Measurement=., ., sum (Measurement, -_Measurement));
run;
Your example data seems inadequate as every subject/date/procedure combination is unique. Here is a SQL solution with extra data added:
data have;
input Subject Type :$12. Date &:anydtdte. Procedure :$12. Measurement;
format date yymmdd10.;
datalines;
500 Initial 15 AUG 2017 Invasive 20
500 Initial 18 SEPT 2018 Surface 35
500 Followup 12 SEPT 2018 Invasive 54
428 Followup 2 JUL 2019 Outer 29
765 Seventh 3 JUL 2018 Other 13
500 Followup 6 NOV 2018 Surface 98
428 Initial 23 FEB 2018 Outer 10
765 Initial 20 AUG 2019 Other 19
610 Third 21 AUG 2018 Invasive 66
610 Initial 27 Mar 2018 Invasive 17
999 Dummy 17 mar 2020 Some 1
999 Dummy 18 mar 2020 Some 2
999 Dummy 19 mar 2020 Some 3
;
proc sql;
create table want as
select *,
(select max(measurement)
from have
where subject=a.subject and type=a.type and procedure=a.procedure
having date = max(date)) / min(measurement) as ratio
from have as a
group by subject, type, procedure
order by subject, date;
quit;
Your example data seems inadequate as every subject/date/procedure combination is unique. Here is a SQL solution with extra data added:
data have;
input Subject Type :$12. Date &:anydtdte. Procedure :$12. Measurement;
format date yymmdd10.;
datalines;
500 Initial 15 AUG 2017 Invasive 20
500 Initial 18 SEPT 2018 Surface 35
500 Followup 12 SEPT 2018 Invasive 54
428 Followup 2 JUL 2019 Outer 29
765 Seventh 3 JUL 2018 Other 13
500 Followup 6 NOV 2018 Surface 98
428 Initial 23 FEB 2018 Outer 10
765 Initial 20 AUG 2019 Other 19
610 Third 21 AUG 2018 Invasive 66
610 Initial 27 Mar 2018 Invasive 17
999 Dummy 17 mar 2020 Some 1
999 Dummy 18 mar 2020 Some 2
999 Dummy 19 mar 2020 Some 3
;
proc sql;
create table want as
select *,
(select max(measurement)
from have
where subject=a.subject and type=a.type and procedure=a.procedure
having date = max(date)) / min(measurement) as ratio
from have as a
group by subject, type, procedure
order by subject, date;
quit;
Hi, I am getting the message "ERROR: Subquery evaluated to more than one row." I am not sure what line is causing this.
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