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Ujjawal
Quartz | Level 8

How can we calculate unique count percentage and normal percentage by a group?

data test;

input Q1 Q2 Q3 Q4 Q5 Age BU;

cards;

1 5 2 3 4 3 3

4 5 2 1 2 1 3

2 4 4 3 2 3 2

1 3 2 5 3 2 3

1 2 4 2 1 2 2;

run;

The following program calculates unique count and count for Q1 by Age.

proc sql noprint;

create table file1 as

select Age,Count(Distinct Q1) as Unique, Count(Q2) as Count

from test

group by Age;

quit;


AgeUniqueCountUnique %%
11125%20%
21225%40%
32250%40%

I am unable to calculate percentage for these two columns. Refer the table above. The percentage is count for each case by total values. Is it possible via data step or PROC SQL?

1 ACCEPTED SOLUTION

Accepted Solutions
stat_sas
Ammonite | Level 13

proc sql;
create table file1 as
select Age,Count(Distinct Q1) as Uniq, Count(Q2) as Count
from test
group by Age;
quit;

proc sql;
select age,uniq,count,(uniq/(select sum(uniq) from file1)) as unique_percent,(count/(select sum(count) from file1)) as cnt_percent
from file1;
quit;

View solution in original post

4 REPLIES 4
jakarman
Barite | Level 11

proc report / tabulate ....

---->-- ja karman --<-----
stat_sas
Ammonite | Level 13

proc sql;
create table file1 as
select Age,Count(Distinct Q1) as Uniq, Count(Q2) as Count
from test
group by Age;
quit;

proc sql;
select age,uniq,count,(uniq/(select sum(uniq) from file1)) as unique_percent,(count/(select sum(count) from file1)) as cnt_percent
from file1;
quit;

PGStats
Opal | Level 21

I don't understand what this is about but you seem to want something like:

proc sql;

select

    age,

    daQ1 label="Q1 Unique",

    caQ1 label="Q1 Count",

    daQ1/dQ2 label="Unique Q1/Q2" format=percent6.1,

    caQ1/cQ2 label="Count Q1/Q2" format=percent6.1

from

    (select age, count(distinct Q1) as daQ1, count(Q1) as caQ1

    from test

     group by age),

    (select count(distinct Q2) as dQ2, count(Q2) as cQ2 from test);

quit;

PG

PG
jakarman
Barite | Level 11

This question has been asked many times before like: https://communities.sas.com/message/115464 , https://communities.sas.com/thread/30943

If you are new to SAS my preference is leaving out any restriction learning all the possibilities with their advantages and disadvantages.
As SAS is more as just a data-step or SQL language I made the reference to procedures, there are several of them.

Reviewing the options with proc means it is remarkable what you can do with that. Base SAS(R) 9.4 Procedures Guide, Second Edition

---->-- ja karman --<-----

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