How do I transform one varible with DATETIME16. format in 2 disctincts time and date variables

[SBuc]

Dear Group, 

I'm trying to work with a big dataset (>1 million lines) file where I have dateandtime data combined in DATETIME16. format. 

These datetime are corresponding to a variable named Creation_date. I am not used with that format.

I want to split the variable Creation_date.in date_created and time_created (the 1st variable would be the date dd/mm/yyyy and the second would be the time). 

I've found some way to do it after manually importing the data using CARDS but this is not feasible with a large dataset.

thank so much!

[Astounding]

SAS has functions that accomplish this simply:

data want;
  set have;
  time_created= timepart(creation_date);
  date_created = datepart(creation_date);
  format date_created ddmmyys10.;
run;

You might also select a format for the TIME_CREATED variable.  You have choices to make here, so this is a good place to start:

https://documentation.sas.com/?docsetId=leforinforref&docsetTarget=p0b2xn5ovzhtjnn1db5g1gg64yhf.htm&...

[TomKari · Accepted solution]

It's not clear from your post if your variable is a character variable that looks like DATETIME16., or if it's already a SAS datetime variable that has a DATETIME16. format applied.

If it's the former, you can use the INPUT function to transform it to a SAS datetime variable, something like the following:

GoodVar = input(BadVar, anydtdtm16.);

Once you have it as a datetime variable, there are a number of options. Easiest is to leave it as a datetime variable, but just use formats to display the date and time. Alternately, the DATEPART and TIMEPART functions will divide the datetime variable.

Tom