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507A
Calcite | Level 5

Hello

 

 

I have datasets, with 20 rows and 51 columns. and I need to delete column(variable) if it has contain specific string.

The string is 'NO'

 

 

dataset (variable name: A, P1, P2, P3, ...... P50)

 

A       P1         P2          P3  .....  P50

0       AP         AP         AP

1       30          25         80

2       50          30         120

3       NO         50         NO

4       NO         20         NO

.

.

.

20 

 

I want to using array statment or macro but I don't have Idea to succesfully solve this problem.

 

I know this is so weired request but I have to do.

 

How can I do that?

 

1 ACCEPTED SOLUTION

Accepted Solutions
Haikuo
Onyx | Level 15

Proc sql maybe not necessary if 1X data step can get the macro variable:

 

data have;
input P1 $ P2 $ P3 $;
datalines;
AP AP AP
30 25 80
50 30 120
NO 50 NO
NO 20 NO
;
 
data _null_;
set have end=done;
array p(*) P1-P3;
array _name(3) $2 _temporary_ ;
do i=1 to dim(p);
if p(i)='NO' then _name(i)=vname(p(i));
end;
if done then call symputx ('del',catx(' ', of _name(*)));
run;


data final;
set have(drop=&del);
run;

View solution in original post

4 REPLIES 4
stat_sas
Ammonite | Level 13

Below is one approach using sql and data steps:

 

data have;
input P1 $ P2 $ P3 $;
datalines;
AP AP AP
30 25 80
50 30 120
NO 50 NO
NO 20 NO
;

 

data want(keep=vname values);
set have;
array p(*) P1-P3;
do i=1 to dim(p);
vname=vname(p(i));
values=p(i);
output;
end;
run;

 

proc sql;
select distinct vname into :del separated by ' ' from want
where values='NO';
quit;

 

data final;
set have(drop=&del);
run;

Haikuo
Onyx | Level 15

Proc sql maybe not necessary if 1X data step can get the macro variable:

 

data have;
input P1 $ P2 $ P3 $;
datalines;
AP AP AP
30 25 80
50 30 120
NO 50 NO
NO 20 NO
;
 
data _null_;
set have end=done;
array p(*) P1-P3;
array _name(3) $2 _temporary_ ;
do i=1 to dim(p);
if p(i)='NO' then _name(i)=vname(p(i));
end;
if done then call symputx ('del',catx(' ', of _name(*)));
run;


data final;
set have(drop=&del);
run;
Astounding
PROC Star

So you do realize then that when you delete the column, the entire column goes.  Not just the NO values, but all the values.

Ksharp
Super User
data have;
input P1 $ P2 $ P3 $;
datalines;
AP AP AP
30 25 80
50 30 120
NO 50 NO
NO 20 NO
;
run;
data _null_;
 set sashelp.vcolumn(keep=libname memname name type 
    where=(libname='WORK' and memname='HAVE' and type='char')) end=last;
 if _n_ eq 1 then call execute('proc sql;create table temp as select');
 call execute(catx(' ','sum(',name,'="NO") as',name));
 if last then call execute('from have;quit;');
  else call execute(',');
run;
proc transpose data=temp out=temp1;run;
proc sql;
 select _name_ into : list separated by ' '
  from temp1
   where col1=0;
quit;
data want;
 set have;
 keep &list;
run;

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