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vldicker
Fluorite | Level 6

I need to take my dataset which provides two days and create a line for every date between the two dates for each person.

 

Example Starting Data

 

ID            Date1        Date2

1              4/4/16       4/6/16

2              7/8/16       7/9/16

 

Example Finished Dataset

 

ID           Date         Date1      Date2

1            4/4/16        4/4/16     4/6/16

1            4/5/16        4/4/16     4/6/16

1            4/6/16        4/4/16     4/6/16

2            7/8/16        7/8/16     7/9/16

2            7/9/16        7/8/16     7/9/16

 

Date being the new variable in the dataset. 

7 REPLIES 7
FreelanceReinh
Jade | Level 19

Try this:

data have;
input ID (Date1 Date2) (:mmddyy.);
cards;
1 4/4/16 4/6/16
2 7/8/16 7/9/16
;

data want;
set have;
do Date=date1 to date2;
  output;
end;
format date: mmddyy8.;
run;

Edit: If you don't like the column order in dataset WANT, you can insert the following line after the data want; statement:

retain ID Date Date1 Date2;
vldicker
Fluorite | Level 6

I actually figured it out thanks to Freelance Reinhard

 

Date Want;

set have;

by id;

if first.id then do;

date=date1;

output;

end;

else;

date=date1;

do unitl (date2);

date+1;

output;

end;

format date mmddyy10.;

run;

FreelanceReinh
Jade | Level 19

@vldicker: I'm afraid that your code doesn't work. Typos ("Date" in line 1, "unitl") apart, the UNTIL condition is incorrect: It is equivalent to "date2 is non-missing and not zero." In most cases (incl. your sample data!) this will be satisfied immediately, so that the body of the DO UNTIL loop is executed only once -- irrespective of the difference between date1 and date2.

 

Edit: Also, the empty ELSE statement does probably not do what you intended (but simply nothing).

 

Edit 2: Here's a corrected version of your approach:

data want;
set have;
date=date1;
do until(date>date2);
  output;
  date+1;
end;
format date mmddyy10.;
run;
vldicker
Fluorite | Level 6
So your code worked the fastest when I tried what you replied with. But it
makes a double copy of everything (which can be deleted with a proc sort)
but is there a reason it does that?



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Reeza
Super User

I don't get a double copy.

 

Post your actual code.

FreelanceReinh
Jade | Level 19

Thanks, @Reeza, for stepping in. I must have overlooked the notification that vldicker replied again. There's so much going on in the forum currently.

 

@vldicker: Sorry for the delayed reply. Are you using two OUTPUT statements (as in your suggested code)? This might explain the "double copies."

ballardw
Super User

@vldicker wrote:
So your code worked the fastest when I tried what you replied with. But it
makes a double copy of everything (which can be deleted with a proc sort)
but is there a reason it does that?


Your code had two output statements. So you get one with the first value of id and then because your ELSE doesn't include any statements you get a second for the first value of id.

Date Want;

set have;

by id;

if first.id then do;

date=date1;

output;

end;

else;

date=date1;

do unitl (date2);

date+1;

output;

end;

format date mmddyy10.;

run;

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