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indox
Obsidian | Level 7

Hello,

 

How can we go from

 

IdLastName1LastName2FirstName1FirstName2
1SmithGarciaJamesMichael
2Jack TomOliver


to

 

IdLastNameFirstName
1SmithJames
1SmithMichael
1GarciaJames
1GarciaMichael
2JackTom
2JackOliver

 

Thank you for help !

 

Regards,

1 ACCEPTED SOLUTION

Accepted Solutions
Ksharp
Super User
data have;
infile cards expandtabs;
input Id	(LastName1	LastName2	FirstName1	FirstName2 ) ($);
cards;
1	Smith	Garcia	James	Michael
2	Jack	 .	Tom	Oliver
;
run;
data want;
 set have;
 if not missing(LastName1) then do;
 lastname=LastName1;firstname=FirstName1;output;firstname=FirstName2;output;
 end;


 if not missing(LastName2) then do;
 lastname=LastName2;firstname=FirstName1;output;firstname=FirstName2;output;
 end;
 drop LastName1	LastName2	FirstName1	FirstName2;
 run;

View solution in original post

8 REPLIES 8
LinusH
Tourmaline | Level 20

IMO the simplest would be data step with assignment and explicit OUTPUT statements.

Data never sleeps
Astounding
PROC Star

First step would be to establish the rest of the rules.  You have shown what to do when LASTNAME2 is the only variable with a missing value.  You would have to establish what should happen for every pattern of missing vs. nonmissing values.  For example, what happens if:

 

  • Both LASTNAME2 and FIRSTNAME2 are missing.
  • Only FIRSTNAME1 is missing.

These aren't the only possibilities.  They're just examples of what needs to be spelled out before the programming can begin.

indox
Obsidian | Level 7

We are going to use the final table to send mails.
If a person has different firstnames or lastnames, we have to send as many letters to reach the person.
If the person has 2 firstnames and only one lastname there will be 2 lines etc...
I don't know if i am clear sorry

Astounding
PROC Star

OK, here's one way to get there.

 

data want;

set have;

if firstname1 > ' ' then do;

   firstname = firstname1;

   if lastname1 > ' ' then do;

      lastname = lastname1;

      output;

   end;

   if lastname2 > ' ' then do;

      lastname = lastname2;

      output;

   end;

end;

if firstname2 > ' ' then do;

   firstname = firstname2;

   if lastname1 > ' ' then do;

      lastname = lastname1;

      output;

   end;

   if lastname2 > ' ' then do;

      lastname = lastname2;

      output;

   end;

end;

keep id firstname lastname;

run;

 

It's a little cluttered, but it's easy to write, read, and interpret.

indox
Obsidian | Level 7

Thanks for your answer.

I knew about this solution is not there a simple way to do it? Because besides firstnames and lastnames, I have 2 adresses 2 birth dates etc...

 

Thanks

Astounding
PROC Star

If you re-shape your data, it is likely you could use SQL to get all combinations.  But are you sure you want to?  So far, you are talking about 4 variables  There may be more.  That means you have 16 pieces of mail for each observation in your data set.  Is that a good idea?  If you add a 5th variable, that increases to 32 pieces of mail per observation.

Ksharp
Super User
data have;
infile cards expandtabs;
input Id	(LastName1	LastName2	FirstName1	FirstName2 ) ($);
cards;
1	Smith	Garcia	James	Michael
2	Jack	 .	Tom	Oliver
;
run;
data want;
 set have;
 if not missing(LastName1) then do;
 lastname=LastName1;firstname=FirstName1;output;firstname=FirstName2;output;
 end;


 if not missing(LastName2) then do;
 lastname=LastName2;firstname=FirstName1;output;firstname=FirstName2;output;
 end;
 drop LastName1	LastName2	FirstName1	FirstName2;
 run;
indox
Obsidian | Level 7
This is beautiful ! thank you !

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