PROC TEMPLATE Error

[railfan1975]

I'm learning how to use PROC TEMPLATE to define a custom style. However, I'm getting an error I don't understand.

My code:
30 proc template;
31 define style styles.mystyle;
32 style table /
33 borderwidth = 1
34 bordercolor = red
35 color = blue
36 ;
37 end;
38 run;

The error:

30 proc template;
31 define style styles.mystyle;
32 style table /
33 borderwidth = 1
34 bordercolor = red
35 color = blue

_
22
76
ERROR 22-322: Syntax error, expecting one of the following: a quoted string, ACTIVELINKCOLOR, BACKGROUND, BACKGROUNDIMAGE,
BORDERCOLOR, BORDERCOLORDARK, BORDERCOLORLIGHT, CONTRASTCOLOR, ENDCOLOR, FONT_FACE, FOREGROUND, IMAGE, LINKCOLOR,
NEUTRALCOLOR, POSTIMAGE, PREIMAGE, STARTCOLOR, VISITEDLINKCOLOR.
ERROR 76-322: Syntax error, statement will be ignored.
36 ;
37 end;
WARNING: Object will not be saved.
38 run;

[Tim_SAS]

What SAS version? I think COLOR is not available until 9.2. Prior to that you use FOREGROUND, which I notice is one of the choices in the error message.

[railfan1975]

Version 9.1.3

FOREGROUND will change the font color?

[Cynthia_sas]

Yes, in SAS 9.1.3, FOREGROUND is the correct attribute for the foreground color of the FONT.

To find the complete list, look in the SAS documentation for ODS under the topic: "Style Attributes and their Values".

cynthia

[railfan1975]

It works! Thanks!