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esirjhm
Calcite | Level 5

The following code seems to have two different results with a 10.5 format when the two values in hexidecimal are identical.  What am I missing?

DATA TEST;                                                 

  HMWID = 62.7;                                             

  LIN_FT = 1;                                               

  RUN;                                                      

DATA AVAL (KEEP = K FT);                                   

  ARRAY LAR{240:799} _TEMPORARY_;                           

  SET TEST END=END;                                         

  PUTLOG HMWID=10.5  +3 HMWID=HEX16.;                       

  HMWID = HMWID * 10;                                       

  PUTLOG 'STORING VALUE '  HMWID=10.5 +3   HMWID=HEX16.;    

  LAR{HMWID} + LIN_FT;                                      

  IF END;                                                   

  DO J = 240 TO (799-40);                                   

     K  = J;                                                

     FT = LAR{J};                                           

     IF FT THEN DO;                                         

        OUTPUT AVAL;                                        

        PUTLOG 'RESTORING VALUE ' K=10.5 +3 HMWID=HEX16.;   

     END;                                                   

  END;                                                      

  RUN; 

Output results...                                                    

HMWID=62.70000    HMWID=423EB33333333333               

STORING VALUE HMWID=627.00000    HMWID=43272FFFFFFFFFFF

RESTORING VALUE K=626.00000    HMWID=43272FFFFFFFFFFF  

1 REPLY 1
DLing
Obsidian | Level 7

Doesn't look like anything is wrong. Don't unerstand why you're showing for RESTORING K not being 627.

What's posted looks like an excerpt from a much larger program, perhaps the culprit is elsewhere and got edited out.

By the way, display format, like 10.5, have nothing to do with internal precision.

1 DATA TEST;

2 HMWID = 62.7;

3 LIN_FT = 1;

4 RUN;

NOTE: The data set WORK.TEST has 1 observations and 2 variables.

NOTE: DATA statement used (Total process time):

real time 0.01 seconds

cpu time 0.01 seconds

 

5

6 DATA AVAL (KEEP = K FT);

7 ARRAY LAR{240:799} _TEMPORARY_;

8 SET TEST END=END;

9 PUTLOG HMWID=10.5 +3 HMWID=HEX16.;

10

11 HMWID = HMWID * 10;

12 PUTLOG 'STORING VALUE ' HMWID=10.5 +3 HMWID=HEX16.;

13 LAR{HMWID} + LIN_FT;

14

15 IF END;

16

17 DO J = 240 TO (799-40);

18 K = J;

19 FT = LAR{J};

20 IF FT THEN DO;

21 OUTPUT AVAL;

22 PUTLOG 'RESTORING VALUE ' K=10.5 +3 HMWID=HEX16.;

23 END;

24 END;

25 RUN;

HMWID=62.70000 HMWID=404F59999999999A

STORING VALUE HMWID=627.00000 HMWID=4083980000000000

RESTORING VALUE K=627.00000 HMWID=4083980000000000

NOTE: There were 1 observations read from the data set WORK.TEST.

NOTE: The data set WORK.AVAL has 1 observations and 2 variables.

NOTE: DATA statement used (Total process time):

real time 0.03 seconds

cpu time 0.01 seconds

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