hi, I have a date 05/13 in a variable named 'date'.
1) now i want to split, date and month. How to split the date as day and month.
2) its is also in character format. how do i convert it to numeric..
date
05/13.
i want this as day month
13 05
SCAN() will allow you to separate the components based on a delimiter, in this case your /.
INPUT() will convert the values to numeric.
Another approach is to read it in as a date and then use DAY() and MONTH() functions.
data example;
have='05/13';
*character extraction;
month_char=scan(have, 1, '/');
day_char=scan(have, 2, '/');
*conversion to numeric;
month_num=input(month_char, 8.);
day_char=input(day_char, 8.);
*same as above but single step;
month_num2=input(scan(have, 1, '/'), 8.);
day_num2=input(scan(have, 2, '/'), 8.);
*date method - requires year or custom informat;
have_date=input(catt(have, '/2020'), mmddyy10.);
month_num3=month(have_date);
day_num3=day(have_date);
run;
SCAN() will allow you to separate the components based on a delimiter, in this case your /.
INPUT() will convert the values to numeric.
Another approach is to read it in as a date and then use DAY() and MONTH() functions.
data example;
have='05/13';
*character extraction;
month_char=scan(have, 1, '/');
day_char=scan(have, 2, '/');
*conversion to numeric;
month_num=input(month_char, 8.);
day_char=input(day_char, 8.);
*same as above but single step;
month_num2=input(scan(have, 1, '/'), 8.);
day_num2=input(scan(have, 2, '/'), 8.);
*date method - requires year or custom informat;
have_date=input(catt(have, '/2020'), mmddyy10.);
month_num3=month(have_date);
day_num3=day(have_date);
run;
Since a SAS date value must have a year there cannot be an informat to create a date from something without a year value.
Your best bet is likely to parse the character value and create numeric values of Month and Day and then create a date with the MDY function where you supply the year value.
month=scan(date,1,'/');
day=scan(date,2,'/');
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