Hi there,
I need your kind help to split a string available in one column of my data into multiple rows based on different bullets such A, B, 1, 2, A., B., C. , A), B), A:, B:, A- and B-. Finally I want to assign an identifier to each row.
DATA have;
text= "1) POLYP AT LEFT COLON: TUBULOVILLOUS. NEGATIVE FOR SERRATED.
2) POLYP AT RIGHT COLON: INFLAMMATORY. NEGATIVE FOR TUBULOVILLOUS.
3. ADENOMA AT RIGHT COLON: INFLAMMATORY. NEGATIVE FOR TUBULOVILLOUS.
4. ADENOMA FROM TRANSVERSE COLON: NEGATIVE FOR INFLAMMATORY BUT SERRATED IS FOUND.
A- ADENOMATOUS TISSUE AT LEFT COLON: TUBULOVILLOUS. NEGATIVE FOR SERRATED.
B- ADENOMATOUS TISSUE AT RIGHT COLON: INFLAMMATORY. NEGATIVE FOR TUBULOVILLOUS.
A: POLYP FROM TRANSVERSE COLON: NEGATIVE FOR INFLAMMATORY BUT SERRATED IS FOUND.
B: POLYP AT LEFT COLON: TUBULOVILLOUS. NEGATIVE FOR SERRATED."
;
RUN;
DATA want;
length text $100 ;
id=1; text="1) POLYP AT LEFT COLON: TUBULOVILLOUS. NEGATIVE FOR SERRATED."; output;
id=2; text="2) POLYP AT RIGHT COLON: INFLAMMATORY. NEGATIVE FOR TUBULOVILLOUS." ; output;
id=3; text="3. ADENOMA AT RIGHT COLON: INFLAMMATORY. NEGATIVE FOR TUBULOVILLOUS." ; output;
id=4; text="4. ADENOMA FROM TRANSVERSE COLON: NEGATIVE FOR INFLAMMATORY BUT SERRATED IS FOUND."; output;
id=5; text="A- ADENOMATOUS TISSUE AT LEFT COLON: TUBULOVILLOUS. NEGATIVE FOR SERRATED."; output;
id=6; text="B- ADENOMATOUS TISSUE AT RIGHT COLON: INFLAMMATORY. NEGATIVE FOR TUBULOVILLOUS." ; output;
id=7; text="A: POLYP FROM TRANSVERSE COLON: NEGATIVE FOR INFLAMMATORY BUT SERRATED IS FOUND."; output;
id=8; text="B: POLYP AT LEFT COLON: TUBULOVILLOUS. NEGATIVE FOR SERRATED."; output;
;
RUN;
Thank you in advance for your kind reply.
And this question: Is it possible to have A. A- or A: in the text as well as the first character set delimiter?
If the answer to @Reeza's question about A. A- A: is yes, Here's a question that might mitigate the problem
Do all desired text items end with a period?
Then you need to provide a more robust example data set that has cases like that to ensure any solution works for your actual data.
I don't know that there will be a robust way to solve this given everything you've said though, except for manually and even then it's hard because the rules are ambiguous.
DATA have; text= "1) POLYP AT LEFT COLON: TUBULOVILLOUS. NEGATIVE FOR SERRATED. 2) POLYP AT RIGHT COLON: INFLAMMATORY. NEGATIVE FOR TUBULOVILLOUS. 3. ADENOMA AT RIGHT COLON: INFLAMMATORY. NEGATIVE FOR TUBULOVILLOUS. 4. ADENOMA FROM TRANSVERSE COLON: NEGATIVE FOR INFLAMMATORY BUT SERRATED IS FOUND. A- ADENOMATOUS TISSUE AT LEFT COLON: TUBULOVILLOUS. NEGATIVE FOR SERRATED. B- ADENOMATOUS TISSUE AT RIGHT COLON: INFLAMMATORY. NEGATIVE FOR TUBULOVILLOUS. A: POLYP FROM TRANSVERSE COLON: NEGATIVE FOR INFLAMMATORY BUT SERRATED IS FOUND. B: POLYP AT LEFT COLON: TUBULOVILLOUS. NEGATIVE FOR SERRATED." ; RUN; data temp; set have; n+1; pid=prxparse('/\b\w\W/'); s=1;e=length(text); call prxnext(pid,s,e,text,p,l); do id=1 by 1 while(p>0); want=substr(text,p,l);output; call prxnext(pid,s,e,text,p,l); end; keep n p text; run; data want; merge temp temp(firstobs=2 keep=n p rename=(n=_n p=_p)); if n=_n then want=substr(text,p,_p-p); else want=substr(text,p); if first.n then id=0; id+1; keep n id want; run;
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