I am new to SAS an I will like to perform this operation in SAS
7-1*0+3/3
(7-1)*0+3/3
(7-1)*0+(3/3)
Thank you
Hi and welcome to the SAS Communities.
data _null_; a=7-1*0+3/3; put a=; a=(7-1)*0+3/3; put a=; a=(7-1)*0+(3/3); put a=; run;
Thanks
How can i write
data _null_;a=7-1*0+3/3; put a=;a=(7-1)*0+3/3; put a=;a=(7-1)*0+(3/3); put a=;run;
in IML or Macro language?
proc iml; a=7-1*0+3/3; print a; a=(7-1)*0+3/3; print a; a=(7-1)*0+(3/3); print a; quit;
Thanks alot.
@Lawongd wrote: Thanks How can i write data _null_;a=7-1*0+3/3; put a=;a=(7-1)*0+3/3; put a=;a=(7-1)*0+(3/3); put a=;run; in IML or Macro language?
The SAS Macro language is used to create sas-code and should not be used for calculations!
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