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chchao
Calcite | Level 5
Dear all,
From F table, could find the F(7,10),0.05=3.14, but SAS output (see the bottom of picture) Pr> F(=3.65) = 0.0639. There was something wrong ?

* SAS code;
data unequal_var; input disease $ time @@; cards; A 36 A 32 A 24 A 35 A 26 A 28 A 32 A 33 A 34 A 29 A 32 B 35 B 24 B 13 B 27 B 22 B 18 B 31 B 30 ; proc ttest; class disease; run;

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FreelanceReinh
Jade | Level 19

Hello @chchao and welcome to the SAS Support Communities!

 

Everything is correct here (as usual). The keyword is "Folded F" -- which means that a factor 2 comes into play in order to perform a two-tailed test. The formula can be found in section "Two-Independent-Sample Design" of the PROC TTEST documentation. To reproduce the p-value (0.0639) with SAS functions you can use PROBF or CDF¹: p=2*(1-probf(230/63, 7, 10))=2*(1-cdf('F', 230/63, 7, 10)). (230/63 is the exact F value 3.65079...)

 

¹ Addendum: ... or SDF: 2*(sdf('F', 230/63, 7, 10))

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FreelanceReinh
Jade | Level 19

Hello @chchao and welcome to the SAS Support Communities!

 

Everything is correct here (as usual). The keyword is "Folded F" -- which means that a factor 2 comes into play in order to perform a two-tailed test. The formula can be found in section "Two-Independent-Sample Design" of the PROC TTEST documentation. To reproduce the p-value (0.0639) with SAS functions you can use PROBF or CDF¹: p=2*(1-probf(230/63, 7, 10))=2*(1-cdf('F', 230/63, 7, 10)). (230/63 is the exact F value 3.65079...)

 

¹ Addendum: ... or SDF: 2*(sdf('F', 230/63, 7, 10))

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