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Danny2020
Calcite | Level 5

I am trying to get the mean value for returns, but different companies contain different number of years, how could i figure these out? many thanks

 

ID Year SizeReturn Average
12016sml-2.1 
12017sml0.25 
12018med0.26-0.26009
21999sml0.5 
22000med-0.8 
22001med0.7 
22002med1.90.575
3 REPLIES 3
acordes
Rhodochrosite | Level 12
Proc Means Data=have;
Class ID;
Var return;
Output out=want mean= / autoname;
Run;
yabwon
Onyx | Level 15

Hi,

 

Two things:

1) how you get-0.26009 out of -2.1, 0.25, and 0.26?

2) do you want to get something like this:

data have;
input
ID 	Year 	Size $	Return 	;
cards;
1	2016	sml	-2.1	 
1	2017	sml	0.25	 
1	2018	med	0.26	
2	1999	sml	0.5	 
2	2000	med	-0.8	 
2	2001	med	0.7	 
2	2002	med	1.9	
;
run;
proc sort data = have;
  by ID year;
run;

data want;

  set have;
  by id;

  if first.ID then _avg = .;
  _avg + return;
  _n + (return>.z);

  if last.id then average = _avg/_n;
  drop _:;

  put _all_;
run;
proc print;
run;

 

Bart

 

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Ksharp
Super User
data have;
input
ID 	Year 	Size $	Return 	;
cards;
1	2016	sml	-2.1	 
1	2017	sml	0.25	 
1	2018	med	0.26	
2	1999	sml	0.5	 
2	2000	med	-0.8	 
2	2001	med	0.7	 
2	2002	med	1.9	
;
run;
proc sql;
create table temp as
select *,mean(return) as mean from have group by id;
quit;
data want ;
 set temp;
 by id;
 if not last.id then call missing(mean);
run;

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