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Posted 04-27-2019 01:18 AM
(856 views)

proc optmodel;

set supply= {"S1","S2"};

set distr= {"SGD","MYD","IDD","VND","THD"};

set plant= {"SG","MY","ID","VN","TH"};

number Suppliercap {supply}=[2000,2000];

number AnnualDemand {plant}=[

150 300 150 150 300];

number timeperiods = 6;

number matcost = 40;

number packcost = 5;

number Leg1Trcost {supply,distr}=[

12 12 14 16 18

14 12 14 18 16] ;

number Leg2Trcost {distr,plant}=[

0 4 4 6 5

3 0 4 4 5

3 4 0 4 6

5 4 6 0 3

5 6 4 3 0];

number Pmin = 1;

number Pmax = 5;

var Firstlegsupply {supply,distr} >= 0;

var Secondlegsupply {distr,plant} >= 0;

var open {distr} binary;

minimize Total_Cost= sum {i in supply,k in distr} Firstlegsupply[i,k]*(Leg1Trcost[i,k]+matcost) +

sum {k in distr,j in plant} Secondlegsupply[k,j]*(Leg2Trcost[k,j]+matcost+packcost);

con MaxS {i in supply} :

sum {k in distr} Firstlegsupply[i,k] <= Suppliercap[i];

con MinD {j in plant} :

sum {k in distr} Secondlegsupply[k,j]*timeperiods = AnnualDemand[j];

con NoStock {k in distr} :

sum {i in supply} Firstlegsupply[i,k] = sum {j in plant} Secondlegsupply[k,j];

con linkingcons{k in distr,j in plant}:

Secondlegsupply[k,j]-2000*open[k]<=0;

con mindistr :

sum{k in distr}open[k]>= Pmin;

con maxdistr :

sum{k in distr}open[k]<= Pmax;

con minqty{k in distr,j in plant}:

Secondlegsupply[k,j]<=25;

con maxqty{k in distr,j in plant}:

Secondlegsupply[k,j]<=100;

solve;

print Total_Cost;

print {k in distr} (sum {i in supply} Firstlegsupply[i,k]);

print Secondlegsupply;

quit;

The above is my code which will output Total cost, and flows during 2 legs of material supply.

In addition to this i want to seperately print Transportation cost during both legs for the optimized quantities.i.e.

1. sum {i in supply,k in distr} Firstlegsupply[i,k]*Leg1Trcost[i,k];

2. sum {k in distr,j in plant} Secondlegsupply[k,j]*Leg2Trcost[k,j];

Could you kindly advise on how to write code for this.

Do i need to define additional variables and assign this equation. As you can see this is portion of objective function. And i want the function to calculate the value based on optimised values for FirstLegsupply and Secondlegsupply.

3 REPLIES 3

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Just use PRINT with parentheses:

print (your expression);

print (your expression);

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Hello Rob,

Thank you very much for your response. I am very sorry for my ignorance as I am new to this software.

I had tried the same but without using parentheses.

With your suggestion, I am able to print the value and they appear just as a number.

In order that the results displayed are self-explanatory, may I know how to associate it with a name. Example for the objective function, the result is displayed as **Total_cost** and then the numeric value.

Your response is highly appreciated and will be of great help.

Regards,

Errol Tauro

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Here are four ways:

```
print "my string";
print (expression);
print "my string" (expression);
impvar myimpvar = expression;
print myimpvar;
num mynum = expression with .sol suffix for each variable;
print mynum;
```

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