Creating a dotted curve and changing the color of the under curve area

[Almutairi]

Hi,

I am trying to submit a paper to a journal which prints graphs in black. The following code gives two nonblack colors to the overlapped curve lines of the two graphs. I would like to know how to adjust this code so I can change (1) one of the curve lines to a dotted curve, (2) change the color of the two histograms to black, one solid and one gradient, and (3) create a white line divides each binwidth, please.

title "Distributions of scaled earnings and earnings before abnormal CFO";
proc sgplot data=compu_graph_EBACFO;
histogram Lagearnings1 / binwidth=0.01 binstart= -0.25 showbins transparency=0.4
name="Scaled earnings" legendlabel="Scaled earnings";
histogram EB_ACFO / binwidth=0.01 binstart= -0.25 showbins transparency=0.5
name="Earnings before abnormal CFO" legendlabel="Earnings before abnormal CFO";
density Lagearnings1 / type=kernel lineattrs=GraphData1; /* optional */
density EB_ACFO / type=kernel lineattrs=GraphData2; /* optional */
xaxis values= (-0.25 to +0.25 by 0.01);
xaxis label="Interval width (0.01)" min=-0.25;
keylegend "Scaled earnings" "Earnings before abnormal CFO" / across=1 position=TopRight location=Inside;
run;

[Rick_SAS]

make your life simple and use the Journal style. Here is an overview of Statistical Graphics using ODS.

Here is the doc for styles and the JOURNAL family of styles.

Start by putting 

ods [DESTINATION] style=Journal;

before your call to PROC SGPLOT and see how it looks.

For example, 

ods html style=Journal;

ods latex style=Journal;

etc

[Almutairi]

Perfect. Thank u Rick as always. 

[DanH_sas]

First of all, you might want to check out your output if you run it using STYLE=JOURNAL2 on your ODS statement; however, the histogram will no be filled in that case.

To get what you requested, try the modified code below. I'm not sure it the histograms will be like you want. Just let us know:

title "Distributions of scaled earnings and earnings before abnormal CFO";
proc sgplot data=compu_graph_EBACFO;
histogram Lagearnings1 / binwidth=0.01 binstart= -0.25 showbins transparency=0.4 fillattrs=(color=black)
name="Scaled earnings" legendlabel="Scaled earnings";
histogram EB_ACFO / binwidth=0.01 binstart= -0.25 showbins transparency=0.5 fillattrs=(color=black) outlineattrs=(color=white)
name="Earnings before abnormal CFO" legendlabel="Earnings before abnormal CFO";
density Lagearnings1 / type=kernel lineattrs=(color=black pattern=solid)
density EB_ACFO / type=kernel lineattrs=(color=black pattern=dot)
xaxis values= (-0.25 to +0.25 by 0.01);
xaxis label="Interval width (0.01)" min=-0.25;
keylegend "Scaled earnings" "Earnings before abnormal CFO" / across=1 position=TopRight location=Inside;
run;

Hope this helps!

Dan

[Almutairi]

Thank you Dan for your quick response. I ran the code but I encountered some errors. See the attachment plz.

[DanH_sas]

My apologies. OUTLINEATTR control for HISTOGRAMS s available in GTL, but not currently in the SG procedures. Also, it should have been PATTERN in the LINEATTRS option, not LINEPATTERN.

If you want to use SGPLOT, and still get your white outlines, you'll have to make a a small ODS style that inherits from a style like JOURNAL2. I'll create one and post back.

Thanks!
Dan

[DanH_sas]

Here's a simple example using the new style. You can adapt it to your original code by just adding the LINEATTRS options to your DENSITY statements.

Thanks!

Dan

proc template;
define style styles.MyJournal;
parent=styles.journal;

style GraphData1 from GraphData1 /
      color = cx000000;
style GraphData2 from GraphData2 /
      color = cx000000;
style GraphOutlines from GraphOutlines /
      contrastcolor = cxFFFFFF;
end;
run;

ods html style=myjournal;
proc sgplot data=sashelp.heart;
histogram weight / transparency=0.4;
histogram cholesterol / transparency=0.4;
density weight / type=kernel lineattrs=(pattern=solid);
density cholesterol / type=kernel lineattrs=(pattern=dot);
run;

[Almutairi]

Thanks Dan.