Hi...Is there something similiar or equivalent to holiday('labor', year) but rather than producing the first Monday in September, the result would the first Monday in August? Thnaks.
data null;
year=2016;
month=8;
format monday date9.;
monday=intnx('week.3',(mdy(month,1,year)),0,'e');
run;
data null;
year=2016;
month=8;
format monday date9.;
monday=intnx('week.3',(mdy(month,1,year)),0,'e');
run;
If you are looking for the same day, one month prior to Labor day, you can do:
data _null_;
date_labor = holiday('LABOR',year(today()));
date_1MonthPrior = intnx('MONTH',date_labor,-1,'S');
format Date_: YYMMDD10.;
put _all_;
stop;
run;
date_labor=2016-09-05 date_1MonthPrior=2016-08-05 _ERROR_=0 _N_=1
data _null_;
x=NWKDOM(1, 2, 8, 2016);
put x= date9.;
run;
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