Hi SAS gurus,
May I ask one question how to take today date + 36 months into future? Using the variable below SAS_extension?
data in.indata;
do year=2010 to year(today());
do month=1 to month(today());
SAS_date=mdy(month,1,year);
output;
end;
end;
format SAS_date date9.;
run;
SAS_extension= SAS_date+36 months *** I would like to take today date + 36 months into future
INTNX - note the 4th/last parameter aligns it, in this case, I've chosen the beginning of the month. You can choose, end or same. Look up the values in the documentation.
date_future36=intnx('month', today(), 36, 'b')
INTNX - note the 4th/last parameter aligns it, in this case, I've chosen the beginning of the month. You can choose, end or same. Look up the values in the documentation.
date_future36=intnx('month', today(), 36, 'b')
data in.indata;
do year=2010 to year(today());
do month=1 to month(today());
SAS_date=mdy(month,1,year);
output;
end;
end;
run;
are you sure this is what you want?
do month=1 to month(today())
will return only the months from January to, say, June for ALL years.
To get all months, you would do better with:
SAS_date = '01JAN2010'd;
do while ( SAS_date <= intnx("MONTH", Today(), 0) );
SAS_date = intnx("MONTH", SAS_date, 1);
output;
end;
Available on demand!
Missed SAS Innovate Las Vegas? Watch all the action for free! View the keynotes, general sessions and 22 breakouts on demand.
Learn how use the CAT functions in SAS to join values from multiple variables into a single value.
Find more tutorials on the SAS Users YouTube channel.