Dear Trusted SAS Users, I am having similar issues. I want to get AIC/BIC values for my Frailty model using a random statement to account for variability between studies in proc phreg. Does anyone have an idea of how this can be calculated? My (tentative) syntax is below, proc phreg data=cvd1c; ods output ParameterEstimates = ParameterEstimates; class meno7cat(ref='50-52 yrs' param=ref) study byc3cat racethnicity5cat education3 smoking_b bmi5cat nochildcat hrtuse_b afb2; model YearsCVD*CVDicd_ever(0)=meno7cat byc3cat racethnicity5cat education3 smoking_b bmi5cat nochildcat hrtuse_b afb2 /ALPHA=0.05 RISKLIMITS=wald; Random study/solution; format meno7cat meno7catf.; run; I am only getting the marginal likelihood value. Can this be equated as -2LogL? Marginal Loglikelihood -87071.6 Full output below, Summary of the Number of Event and CensoredValuesTotal Event Censored PercentCensored 180207 8216 171991 95.44 Convergence Status Convergence criterion (PCONV=0.0001) satisfied. Marginal Loglikelihood -87071.6 Testing Global Null HypothesisTest Chi-Square AdjustedDF Pr > ChiSqLikelihood RatioWald 3291.1031 51.44 <.0001 3660.9894 51.44 <.0001 Covariance Parameter EstimatesCov Parm REML Estimate StandardErrorstudy 0.4042 0.1813
... View more