Good morning my SAS friends: Here is a question about SAS basic computing As we know, confidence interval (CLASS) is a usual statistical procedure where we group many observations in CLASSES considering the upper and lower limits and the number of observations (n) as grouping criteria (see this example http://www.vitutor.com/statistics/descriptive/frequency_distribution.html) Considering these data: 3, 15, 24, 28, 33, 35, 38, 42, 43, 38, 36, 34, 29, 25, 17, 7, 34, 36, 39, 44, 31, 26, 20, 11, 13, 22, 27, 47, 39, 37, 34, 32, 35, 28, 38, 41, 48, 15, 32, 13. In this case, 48 − 3 = 45. For the purpose of this table, increase the number to 50. Therefore, 50 : 5 = 10 intervals. xi fi Fi ni Ni [0, 5) 2.5 1 1 0.025 0.025 [5, 10) 7.5 1 2 0.025 0.050 [10, 15) 12.5 3 5 0.075 0.125 [15, 20) 17.5 3 8 0.075 0.200 [20, 25) 22.5 3 11 0.075 0.275 [25, 30) 27.5 6 17 0.150 0.425 [30, 35) 32.5 7 24 0.175 0.600 [35, 40) 37.5 10 34 0.250 0.850 [40, 45) 42.5 4 38 0.100 0.950 [45, 50) 47.5 2 40 0.050 1 40 1 Is there any SAS Statement that could help??? thanks in advance
... View more