Hi there, I have three keys that I will use them join all data sources. I wanted to create an order for the three keys once they are sorted ascending. Here is what the data looks like:
x1 | x2 | x3 |
1 | 1 | 1 |
1 | 1 | 201 |
1 | 20 | 1 |
1 | 20 | 202 |
11 | 1 | 1 |
11 | 1 | 203 |
11 | 21 | 1 |
11 | 21 | 2 |
Here is what I wanted:
x1 | x2 | x3 | o1 | o2 | o3 |
1 | 1 | 1 | 1 | 1 | 1 |
1 | 1 | 201 | 1 | 1 | 2 |
1 | 20 | 1 | 1 | 2 | 1 |
1 | 20 | 202 | 1 | 2 | 2 |
11 | 1 | 1 | 2 | 1 | 1 |
11 | 1 | 203 | 2 | 1 | 2 |
11 | 21 | 1 | 2 | 2 | 1 |
11 | 21 | 2 | 2 | 2 | 2 |
wanted to do it efficiently and avoid multiple sorting. Thanks.
I can't test it right now, but I think this is where you are headed:
data want;
set have;
by x1 x2 x3;
if first.x1 then do;
o1 + 1;
o2 = 1;
o3 = 1;
end;
else if first.x2 then do;
o2 + 1;
o3 = 1;
end;
else if first.x3 then o3 + 1;
run;
What's the logic for the keys, O1, O2, O3?
@yymissing wrote:
Hi there, I have three keys that I will use them join all data sources. I wanted to create an order for the three keys once they are sorted ascending. Here is what the data looks like:
x1 x2 x3 1 1 1 1 1 201 1 20 1 1 20 202 11 1 1 11 1 203 11 21 1 11 21 2 Here is what I wanted:
x1 x2 x3 o1 o2 o3 1 1 1 1 1 1 1 1 201 1 1 2 1 20 1 1 2 1 1 20 202 1 2 2 11 1 1 2 1 1 11 1 203 2 1 2 11 21 1 2 2 1 11 21 2 2 2 2
wanted to do it efficiently and avoid multiple sorting. Thanks.
I can't test it right now, but I think this is where you are headed:
data want;
set have;
by x1 x2 x3;
if first.x1 then do;
o1 + 1;
o2 = 1;
o3 = 1;
end;
else if first.x2 then do;
o2 + 1;
o3 = 1;
end;
else if first.x3 then o3 + 1;
run;
yes, that is what I needed. thanks
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