making a counting process format from long format

[withpeople86]

id	year	deathy	deathm	deathd
1	2010
1	2011
1	2012
1	2013
1	2014
1	2015	2015	3	17
2	2010
2	2011
2	2012
2	2013
2	2014
2	2015
2	2016
2	2017
3	2010
3	2011	2011	3	1

If I have data looking like this, to conduct cox analysis should I make a table looking like below?

Also, what codes should I use to make a table like this?

id	year	deathy	deathm	deathd	start	finish
1	2010				0	365
1	2011				366	730
1	2012				731	1096
1	2013				1097	1462
1	2014				1463	1828
1	2015	2015	3	17	1829	77.83333
2	2010				0	365
2	2011				366	730
2	2012				731	1096
2	2013				1097	1462
2	2014				1463	1828
2	2015				1829	2194
2	2016				2195	2560
2	2017				2561	2926
3	2010				0	365
3	2011	2011	3	1	366	61.83333

Thanks in advance.

[Astounding]

Here are some features about your plan that stand out as questionable.

Why should the start for each ID be at 0 and not at 1?  It's inconsistent to go from 0 to 365 for year 1, but 366 to 730 for year 2.

Why use fractional days?  SAS is perfectly capable of counting days from January 1 to March 17.

Why should the final FINISH value be lower than the final START value?  Should we be adding those together to get the right FINISH?

I'm not claiming to have answers to these questions, just pointing out that these issues are red flags.

The programming isn't that difficult, but designing the target result takes some work.

[withpeople86]

I am sorry that I made some mistakes and your comment is correct.

I'm attaching the new table here. Is this correct now?

id	year	deathy	deathm	deathd	start	finish
1	2010				1	365
1	2011				366	730
1	2012				731	1096
1	2013				1097	1462
1	2014				1463	1828
1	2015	2015	3	17	1829	1907
2	2010				1	365
2	2011				366	730
2	2012				731	1096
2	2013				1097	1462
2	2014				1463	1828
2	2015				1829	2194
2	2016				2195	2560
2	2017				2561	2926
3	2010				1	365
3	2011	2011	3	1	366	428

[Astounding]

That looks better.  I can't really advise you about the analysis, but I can give you some direction about creating the START and FINISH variables.  Try it this way:

proc sort data=have;
   by id year;
run;

data want;
   set have;
   by id year;
   retain start finish;;
   days_in_current_feb = day(mdy(3, 1, year) - 1);
   if first.id then do;
      start = 1;
      finish = 365 - 28 + days_in_current_feb;
      if deathy > . then finish = mdy(deathm, deathd, deathy) -
                 intnx('year', mdy(1, 1, year), 0) + 1;
   end;
   else do;
      start + 365 - 28 + days_in_current_feb;
      if deathy = . then finish + 365 - 28 + days_in_current_feb;
      else finish + mdy(deathm, deathd, deathy) - start;
   end;
run;

FOR THE MOMENT:  Sorry, this is incomplete.  Once my brain turned to mush, I needed a break.  I will get back to it later to fix the rest of it.

[Astounding]

OK, here's the retry:

proc sort data=have;
   by id year;
run;

data want;
   set have;
   by id year;
   retain start finish;
   days_in_current_year = mdy(1, 1, year+1) - mdy(1, 1, year);
   if first.id then do;
      start = 1;
      finish = days_in_current_year;
   end;
   else do;
      start = finish + 1;
      finish = finish + days_in_current_year;
   end;
   if deathy > . then do;
      finish = finish - days_in_current_year;
      finish = finish + mdy(deathm, deathd, deathy) - mdy(1, 1, year) + 1;
   end;
run;

It looks about right, but test it to see if the final calculation for a death date needs to be adjusted by a day. 

[ScottBass]

Edit:  I posted this without first seeing Astounding's solution.  Our approaches are virtually identical.

I thought this would be fun...this is what I came up with:

data have;
   length id year deathy deathm deathd 8;
   infile datalines truncover;
   input id year deathy deathm deathd;
   datalines;
1   2010            
1   2011            
1   2012            
1   2013            
1   2014            
1   2015   2015   3   17
2   2010            
2   2011            
2   2012            
2   2013            
2   2014            
2   2015            
2   2016            
2   2017            
3   2010            
3   2011   2011   3   1
;
run;

data want;
   length id year deathy deathm deathd start finish 8;
   infile datalines truncover;
   input id year deathy deathm deathd start finish;
   datalines;
1  2010     .  .  .     1    365
1  2011     .  .  .   366    730
1  2012     .  .  .   731   1096
1  2013     .  .  .  1097   1462
1  2014     .  .  .  1463   1828
1  2015  2015  3  17 1829   1907
2  2010     .  .  .     1    365
2  2011     .  .  .   366    730
2  2012     .  .  .   731   1096
2  2013     .  .  .  1097   1462
2  2014     .  .  .  1463   1828
2  2015     .  .  .  1829   2194
2  2016     .  .  .  2195   2560
2  2017     .  .  .  2561   2926
3  2010     .  .  .     1    365
3  2011  2011  3  1   366    428
;
run;

data test;
   set have;
   by id year;
   * derive date from year ;
   date=mdy(1,1,year);
   * derive number of days in the year ;
   num_days=intck('day',intnx('year',date,0,'B'),intnx('year',date,1,'B'));
   * if death, derive number of days to death ;
   if nmiss(deathy,deathm,deathd)=0 then
   num_days=intck('day',intnx('year',date,0,'B'),mdy(deathm,deathd,deathy));
   * reset if first ID ;
   if first.id then do;
      start=1;
      finish=num_days;
   end;
   else do;
      start=finish+1;
      finish+num_days;  * automatically retained ;
   end;
   drop date;
*   drop num_days;
run;

proc compare base=want comp=test;
run;

However, it doesn't exactly match your desired output.  Perhaps you can run with this and fix the code?  Or perhaps your desired output is slightly off?

Hope this helps...

P.S.: In the future, can you post your problems with a self-contained data step containing datalines for your data?  This will save us from having to cut-and-paste your data into a working data step.