logical operators

[capam]

I'm trying to solve a logical problem:

two binary inputs with up to 6 digits starting from right to left.
Example inputs are below. Note that the sas table has them right justified.

100
1001
101111
111111
111000
100000
100000
110
110
110111
11100
1

The output I'm looking for is based on an AND operator as follows:

operator(1,111110) = 0

operator(1,111111) = 1

operator(100,111111) = 100
operator(100110,111111) = 100110
operator(11100,111011) = 11000

Thanks for your time and help.

Steve

[Shmuel]

Your input displays one variable.

Each of your operators use two arguments. where from are those arguments taken? 

What is the logic of your operators ?

Your input includes a number 100000 which is not of any operator.

It is not clear what you want. 

[capam]

Hi,
The source is a table which contains 2 variables of interest which have the same general construct of binary digits that may be up to 6 digits in length.
They are to be multiplied according to an AND operator as shown in the text.

[FreelanceReinh · Accepted solution]

Hi @capam,

This looks like an opportunity to use the BAND function.

Example:

data have;
input (arg1 arg2) (:binary.);
format arg: binary6.;
cards;
1 111110
1 111111
100 111111
100110 111111
11100 111011
;

data want;
set have;
result=input(put(band(arg1, arg2),binary6.),6.);
run;

Result:

 arg1      arg2     result

000001    111110         0
000001    111111         1
000100    111111       100
100110    111111    100110
011100    111011     11000

Note that I've converted the result to decimal numbers in order to get rid of the leading zeros. For further processing as binary values, however, you should use band(arg1, arg2) without input(put(...)).