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vijaypratap0195
Obsidian | Level 7

Explain why I am getting all the EVEN values when I am doing i+j as a final result in the nested loop:

 

data floyd;
array arr(*) col1-col5;
do i=1 to 5;
	do j=1 to i;
		arr(i) = i+j; 
	end;	
	output;
end;
drop i j;
run;
proc print; run;

vijaypratap0195_0-1693674912395.png

As per my understanding output has to be :

Expected output:

vijaypratap0195_1-1693675160236.png

and so on.........

Can anyone please explain.

 

1 ACCEPTED SOLUTION

Accepted Solutions
Tom
Super User Tom
Super User

No.

You seem to have confused which index variable represents the observation number (aka ROW) and which one represents the variable number (aka COLUMN).

 

It would also be clearer to empty the array after you write it to see what you are really doing.

data floyd;
array arr[*] col1-col5;
do i=1 to 5;
	do j=1 to i;
		arr[i] = i+j; 
	end;	
	output;
  call missing(of arr[*]);
end;
drop i j;
run;

Result

Obs    col1    col2    col3    col4    col5

 1       2       .       .       .       .
 2       .       4       .       .       .
 3       .       .       6       .       .
 4       .       .       .       8       .
 5       .       .       .       .      10

So when I=2 you write two different values into ARR[2], so only the final one, 4, remains.

 

It becomes clearer is you use ROW and COL as the index variable names.

Now it become clearer that you wanted:

arr[col] = row+col;

Instead of

arr[row] = row+col;

Try

data floyd;
array arr[*] col1-col5;
do row=1 to 5;
	do col=1 to row;
		arr[col] = row+col; 
	end;	
	output;
end;
drop row col;
run;
proc print; run;

View solution in original post

2 REPLIES 2
Tom
Super User Tom
Super User

No.

You seem to have confused which index variable represents the observation number (aka ROW) and which one represents the variable number (aka COLUMN).

 

It would also be clearer to empty the array after you write it to see what you are really doing.

data floyd;
array arr[*] col1-col5;
do i=1 to 5;
	do j=1 to i;
		arr[i] = i+j; 
	end;	
	output;
  call missing(of arr[*]);
end;
drop i j;
run;

Result

Obs    col1    col2    col3    col4    col5

 1       2       .       .       .       .
 2       .       4       .       .       .
 3       .       .       6       .       .
 4       .       .       .       8       .
 5       .       .       .       .      10

So when I=2 you write two different values into ARR[2], so only the final one, 4, remains.

 

It becomes clearer is you use ROW and COL as the index variable names.

Now it become clearer that you wanted:

arr[col] = row+col;

Instead of

arr[row] = row+col;

Try

data floyd;
array arr[*] col1-col5;
do row=1 to 5;
	do col=1 to row;
		arr[col] = row+col; 
	end;	
	output;
end;
drop row col;
run;
proc print; run;
vijaypratap0195
Obsidian | Level 7

Very depth explanation, Thank you.

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