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Dominus
Obsidian | Level 7

I want to generate a series SAS code like:

data want;
    length name label $ 200.;
    name  = "country='Country_A'";
    label = "Country_A";
    output;

    name  = "country='Country_B'";
    label = "Country_B";
    output;

    name  = "country='Country_C'";
    label = "Country_C";
    output;

    *(...etc. so many countries, ie: Country_A to Country_Z);
run;

 

Is there a simple way in SAS to get there that I can generate such code just by typing less words.

 

Array?Macro? or any other methods?

 

Thanks in advance.

 

Best regards.

1 ACCEPTED SOLUTION

Accepted Solutions
andreas_lds
Jade | Level 19

This is indeed a strange requirement, but easy to solve:

data want;
    length 
      name label $ 200
      i 8
   ;
   drop i;

   do i = rank('A') to rank('Z');
      name  = cats("country='Country_", byte(i), "'");
      label = cats("Country_", byte(i));
      output;
   end;
run;

View solution in original post

10 REPLIES 10
PeterClemmensen
Tourmaline | Level 20

Why do you want to do this? Seems to be part of a bigger problem?

Dominus
Obsidian | Level 7
Cause this is a necessary data step to create a conditional judgement dataset for other calculation.
Dominus
Obsidian | Level 7
Or a simple way to create the want dataset
andreas_lds
Jade | Level 19

This is indeed a strange requirement, but easy to solve:

data want;
    length 
      name label $ 200
      i 8
   ;
   drop i;

   do i = rank('A') to rank('Z');
      name  = cats("country='Country_", byte(i), "'");
      label = cats("Country_", byte(i));
      output;
   end;
run;
Dominus
Obsidian | Level 7
Thank you for the answer, I'll try it. Actually, the country names are not a sequence.
PeterClemmensen
Tourmaline | Level 20

Then what defines your country names? Do you have them in a separate data set or? 

Dominus
Obsidian | Level 7
Not a separate data set. Maybe I can put them in a list or a data set.
Dominus
Obsidian | Level 7

Thanks  you. I got what I want.

data want;
    length name label $ 200 i 8;

    array country[6] $100 ('Country A' 'Country B' 'Country C'
                           'Country D' 'Country E' 'Country F');

    do i = 1 to 6;
        name  = cats("country='", country[i], "'");
        label = cats(country[i]);
        output;
    end;

    drop i country: ;
run;
gamotte
Rhodochrosite | Level 12

@Dominus,

 

Note that you can avoid creating actual columns in your dataset by declaring your array as temporary.

 

    array country[6] $100 _TEMPORARY_ ('Country A' 'Country B' 'Country C'
                           'Country D' 'Country E' 'Country F') 
Dominus
Obsidian | Level 7
Thank you for the useful tips.

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