How to find out the difference between two datatime values

[vThanu]

Hi All,

 I want to find out the diffrerence between two date values as per that day wise..

example;

data have;
input id startdate enddate;
informat startdate enddate datetime20.;
format startdate enddate datetime20.;
cards;
1 1May2019:11:10:00 2May2019:00:30:00
;
run;

If I conider the time format as 12 hrs then the difference is 1hr 30 mins, 

1 hrs for 1st of may and 30 mins for 2 of may. 

like wise I want to find out the difference between two datatime values..

thanks in advance

[PeterClemmensen]

How do you distinguishe 11am to 11pm reading your data like this? 

[vThanu]

Consider as 24 hrs time format..
cards;
1 1May2019:23:10:00 2May2019:00:30:00
;
run;

[Tom]

The difference between two datetime values is a number of seconds.

dur_seconds = enddatetime - startdatetime;

To find the difference in DAYS convert them to date values first.

dur_days= datepart(enddatetime) - datepart(startdatetime);

Or divide the seconds by the number of seconds in a day.

dur_days = int(dur_seconds/'24:00't);

[ScottBass]

Your question isn't clear.  Please restate your logic as to why your sample data should return 1.5 hours.

Regardless, perhaps this helps...or not 🙂

data have;
input id startdate enddate;
informat startdate enddate datetime20.;
format startdate enddate datetime20.;
cards;
1 1May2019:23:10:00 2May2019:00:30:00
2 1May2019:23:10:00 5May2019:12:34:56
;
run;

data want;
   set have;
   day_diff=intck('dtday',startdate,enddate);
   hour_diff=intck('hour',startdate,enddate);   
   min_diff=intck('minute',startdate,enddate);
   sec_diff=intck('second',startdate,enddate);
   hours_frac1=min_diff/60;
   hours_frac2=sec_diff/(60*60);
   mins_frac=sec_diff/60;
run;

See the doc for additional options for the INTCK function.

[vThanu]

Here we are getting difference between two date like 1 day or 80 mins so on…..
but what I am exactly looking is in that 80 mins (1May2019:23:10:00 - 2May2019:00:30:00)
50 mins in 1st of May and 30 mins for 2nd of May.

I am looking for the split, if the date/day changes then it should show into separately 50mins & 30 mins.

Hope you got my point.
Thanks in advance

[Tom]

To find the time in the last day just use TIMEPART() on the datetime value.

To find the time left in a day the take difference between now and the beginning of tomorrow.

now=datetime();
rest_of_day = intnx('dtday',now,1,'B') - now;

Or perhaps between now and end of today?  

rest_of_day = intnx('dtday',now,0,'E') - now;

Play with it until you get total to be 80 minutes and not 79 minutes and 59 seconds or 80 minutes and 1 second.