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zishaq
Obsidian | Level 7

Hi,

I have a character variable called employment_flag of length 12 which either contains the values 1 or 0. 

 

For example:

 

010000000010

011100100001

 

I want to find out the longest string of consecutive zeros between the first and last 1 for each value in this variable. For example, the answer for row 1 should be 8 and row 2 should be 4. Note that in example 2 we have a string of 2 zeros and 4 zeros but I'm interested in the longest string.

 

Any help is much appreciated!

 

Thanks

1 ACCEPTED SOLUTION

Accepted Solutions
FreelanceReinh
Jade | Level 19

Hi @zishaq,

 

Here's another (but very similar) suggestion in view of the condition "between the first and last 1":

data have;
input c $12.;
cards;
010000000010
011100100001
;

data want;
set have;
do _n_=2 to countw(c,'1','m')-1;
  m=max(m,lengthn(scan(c,_n_,'1','m')));
end;
run;

In case of less than two 1s in the string the above solution would (deliberately) return a missing value.

View solution in original post

2 REPLIES 2
ballardw
Super User

@zishaq wrote:

Hi,

I have a character variable called employment_flag of length 12 which either contains the values 1 or 0. 

 

For example:

 

010000000010

011100100001

 

I want to find out the longest string of consecutive zeros between the first and last 1 for each value in this variable. For example, the answer for row 1 should be 8 and row 2 should be 4. Note that in example 2 we have a string of 2 zeros and 4 zeros but I'm interested in the longest string.

 

Any help is much appreciated!

 

Thanks


One way:

data example;
   input x :$12.;
   longest=0;
   do i=1 to countw(x,'1');
      longest = max(longest, length(scan(x,i,'1')));
   end;
   drop i;
datalines;
010000000010
011100100001
;

The above code treats the 1 as delimiter for both the countw and scan functions to break the string up into "words" consisting of only 0 and uses the length function to return the number of characters.

FreelanceReinh
Jade | Level 19

Hi @zishaq,

 

Here's another (but very similar) suggestion in view of the condition "between the first and last 1":

data have;
input c $12.;
cards;
010000000010
011100100001
;

data want;
set have;
do _n_=2 to countw(c,'1','m')-1;
  m=max(m,lengthn(scan(c,_n_,'1','m')));
end;
run;

In case of less than two 1s in the string the above solution would (deliberately) return a missing value.

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